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Rama09 [41]
3 years ago
10

Which of the following is not a benefit of the water cycle?

Chemistry
2 answers:
BigorU [14]3 years ago
8 0

Answer:

4th line

Explanation:

-water cycle helps regulate the temperature on the Earth.

Andrej [43]3 years ago
7 0

Answer:

I believe it is D

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The solubility of two slightly soluble salts of M^2+ , MA and MZ_2, are the same, 4 x 10^â4 mol/L.
LekaFEV [45]

Answer:

a) MZ₂

b) They have the same concentration

c) 4x10⁻⁴ mol/L

Explanation:

a) The solubility (S) is the concentration of the salt that will be dissociated and form the ions in the solution, the solubility product constant (Kps) is the multiplication of the concentration of the ions elevated at their coefficients. The concentration of the ions depends on the stoichiometry and will be equivalent to S.

The salts solubilization reactions and their Kps values are:

MA(s) ⇄ M⁺²(aq) + A⁻²(aq) Kps = S*S = S²

MZ₂(aq) ⇄ M⁺²(aq) + 2Z⁻(aq) Kps = S*S² = S³

Thus, the Kps of MZ₂ has a larger value.

b) A saturated solution is a solution that has the maximum amount of salt dissolved, so, the concentration dissolved is solubility. As we can notice from the reactions, the concentration of M⁺² is the same for both salts.

c) The equilibrium will be not modified because the salts have the same solubility. So, let's suppose that the volume of each one is 1 L, so the number of moles of the cation in each one is 4x10⁻⁴ mol. The total number of moles is 8x10⁻⁴ mol, and the concentration is:

8x10⁻⁴ mol/2 L = 4x10⁻⁴ mol/L.

7 0
3 years ago
Consider the following reaction where Kc = 1.80×10-2 at 698 K:2 HI (g) H2 (g) + I2 (g)A reaction mixture was found to contain 0.
Iteru [2.4K]

Answer:

Answer for the given statements: (1) T , (2) F , (3) T , (4) F , (5) F

Explanation:

At the given interval, concentration of HI = \frac{0.304}{1}M=0.304M

Concentration of H_{2} = \frac{5.07\times 10^{-2}}{1}M=5.07\times 10^{-2}M

Concentration of I_{2} = \frac{4.57\times 10^{-2}}{1}M=4.57\times 10^{-2}M

Reaction quotient,Q_{c} , for this reaction = \frac{[H_{2}][I_{2}]}{[HI]^{2}}

species inside third bracket represents concentrations at the given interval.

So, Q_{c}=\frac{(5.07\times 10^{-2})\times (4.57\times 10^{-2})}{(0.304)^{2}}=2.51\times 10^{-2}

So, the reaction is not at equilibrium.

As Q_{c}> K_{c} therefore reaction must run in reverse direction to reduce Q_{c} and make it equal to K_{c}. That means HI(g) must be produced and H_{2} must be consumed.

3 0
2 years ago
What is the ph of a 0.20 M solution of NH4Cl? [Kb(NH3) = 1.8 x 10^-5]
Pavlova-9 [17]

"NH4+ <----> NH3 + H+  

The constant of this equilibrium is: K = Kw / Kb = 1 x 10^-14 / 1.8 x 10^-5 =5.56 x 10^-10  

5.56 x 10^-10 = x^2 / 0.20-x  

x = [H+] =1.1 x 10^-5 M  

pH = 5.0"

8 0
3 years ago
Read 2 more answers
The water table is the..
Zielflug [23.3K]
The upper surface of the zone of saturation is called the water table
6 0
3 years ago
IDENTIFY THE NUMBER OF SIGNIFICANT FIGURES IN EACH OF THESE MEASUREMENTS OF AN OBJECT: 76.47 AND 76.59
murzikaleks [220]

Answer:

they both have 4 sig figs:)

Explanation:

8 0
2 years ago
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