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AleksandrR [38]
3 years ago
8

NEED HELP!!!! 10 POINTS!!

Physics
2 answers:
alexira [117]3 years ago
6 0
I think it may be C. Good luck
Karolina [17]3 years ago
5 0

. i think the answer could be c

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A 0.0450-kg golf ball initially at rest is given a speed of 25.0 m/s when a club strikes. If the club and ball are in contact fo
LuckyWell [14K]

Answer:

Average force, F = 562.5 N

Explanation:

Mass of the golf ball, m = 0.045 kg

Initially, it is at rest, u = 0

Final speed of the ball, v = 25 m/s

The club and the ball are in contact for, t=2\ ms=2\times 10^{-3}\ s

We need to find the average force acting on the ball. It can be calculated using the formula as :

F\times t=m(v-u)

F=m\dfrac{v-u}{t}

F=0.045\times \dfrac{25}{2\times 10^{-3}}  

F = 562.5 N

So, the average force acting on the ball is 562.5 N. Hence, this is the required solution.

5 0
4 years ago
2-The amount of internal energy needed to raise the temperature of 0.25kg of water by 0.2°C is 209.3 J. How fast must a 0.25 kg
Yakvenalex [24]

Answer:

40.92 m/s

Explanation:

The computation is shown below:

Ek = 1 ÷2mv²...............................(1)

v = √(2Ek/m).......................... (2)

Here EK denotes kinetic energy

m denotes mass

v denotes velocity

Given that

m = 0.25kg and Ek = 209.3J

So,

v = √(2×209.3 ÷0.25)

= √1674.4

= 40.92 m/s

7 0
3 years ago
1. A base-ball of mass 0.3kg approaches the bat at a speed of 30 miles/hour and when the ball hits the bat for 0.5 s, it started
andre [41]

Answer:

I = 27kg.mi/h

Explanation:

In order to calculate the impulse of the ball, you use the following formula:

I=m\Delta v  =m(v-v_o)      (1)

m: mass of the ball = 0.3kg

v: speed of the ball after the bat hit it = 60mi/h

vo: speed of the ball before the bat hit it = 30mi/h

You replace the values of all parameters in the equation (1):

I=(0.3kg)(60mi/h-(-30mi/h))=27kg\frac{mi}{h}

where the minus sign of the initial velocity means that the motion of the ball is opposite to the final direction of such a motion.

The imulpse of the ball is 27 kg.miles/hour

5 0
4 years ago
When a pendulum is at the position all the way to the left when it is swinging (at the top of the arc), what is true of the kine
Nadusha1986 [10]
Potential energy + kinetic energy = constant at every moment in time

At the highest point:

potential energy is at its maximum 
kinetic energy is zero
8 0
3 years ago
Read 2 more answers
B
SVEN [57.7K]

Answer:

Frequency = 1,550Hz

Explanation:

To solve this we can use the equation: f=\frac{v}{\lambda}

(frequency = velocity/wavelength).

We are given the information that the wavelength is 22cm and the speed is 340m/s. The first step is to make sure everything is in the correct units (SI units), and to convert them if needed. The SI Units for velocity and wavelength are m/s and m respectively. This means we need to convert 22cm into meters, which we can do by dividing by 100, (as there are 100cm in a meter). 22/100 = 0.22m

Now we can substitute these values into the formula and calculate to solve:

f=\frac{340}{0.22} \\\\f=1545.454...

Simplify to 3 significant figures:

f = 1,550Hz

(Which I believe is just below a G6 if you were interested)

Hope this helped!

4 0
3 years ago
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