Explanation:
First we will convert the given mass from lb to kg as follows.
157 lb = 
= 71.215 kg
Now, mass of caffeine required for a person of that mass at the LD50 is as follows.
= 12818.7 mg
Convert the % of (w/w) into % (w/v) as follows.
0.65% (w/w) = 
= 
= 
Therefore, calculate the volume which contains the amount of caffeine as follows.
12818.7 mg = 12.8187 g = 
= 1972 ml
Thus, we can conclude that 1972 ml of the drink would be required to reach an LD50 of 180 mg/kg body mass if the person weighed 157 lb.
Answer:
sometimes harmful and sometimes beneficial
Answer:
The total amount of CO₂ produced will be = 20680 kg/year
The reduction in the amount of CO₂ emissions by that household per year = 3102 kg/year
Explanation:
Given:
Power used by household = 14000 kWh
Fuel oil used = 3400 L
CO₂ produced of fuel oil = 3.2 kg/L
CO₂ produced of electricity = 0.70 kg/kWh
Now, the total amount of CO₂ produced will be = (14000 kWh × 0.70 kg/kWh) + (3400 L × 3.2 kg/L)
⇒ The total amount of CO₂ produced will be = 9800 + 10880 = 20680 kg/year
Now,
if the usage of electricity and fuel oil is reduced by 15%, the reduction in the amount of the CO₂ emission will be = 0.15 × 20680 kg/year = 3102 kg/year
Answer:
14 m/s
Explanation:
Step One:
Given data:
mass of automobile m= 1700kg
Force F= 170,000 N
time t= 0.14s
v= ??
Required
The velocity of the car
Step two:
From the expression given below, we can find the velocity
Ft= mv
make v subject of the formula
v= Ft/m
v= 170000*0.14/1700
v=23800/1700
v=14 m/s
