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alexandr1967 [171]
2 years ago
11

Please help me !! Ignore whatever I entered !!

Mathematics
1 answer:
riadik2000 [5.3K]2 years ago
6 0

Answer:

thanks thanks thanks thanks for your points

Step-by-step explanation:

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Solve for n 3(n+5)>_3n+8
Rasek [7]

Answer:

No answer

Step-by-step explanation:

INCORRECT QUESTION

4 0
3 years ago
If f(x) = 2x−5, then what is the value of f(2) + f(5)
DochEvi [55]
First of all f(2)=2(2)-5=-1 and f(5)=2(5)-5=5
so
f(2)+f(3)=-1+5=4
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3 years ago
“Find two positive numbers such that the sum to 108, and the product of the first with the square of the second is maximum”
dsp73

Answer:

36 and 72

Step-by-step explanation:

5 0
3 years ago
The notation Ak meas the matrix A Multiplied with itself k times (a) For the 2×2 identity matrix I, show that I2 =I (b)For the n
djverab [1.8K]

Answer:

Entries of I^k are are also identity elements.

Step-by-step explanation:

a) For the 2×2 identity matrix I, show that I² =I

I^{2}=\left[\begin{array}{cc}1&0\\0&1\end{array}\right] \times \left[\begin{array}{cc}1&0\\0&1\end{array}\right] \\\\=\left[\begin{array}{cc}1\times 1+0\times 0&1\times 0+0\times 1\\0\times 1+1\times 0&0\times 0+1\times1\end{array}\right] \\\\=\left[\begin{array}{cc}1&0\\0&1\end{array}\right]

Hence proved  I² =I

b) For the n×n identity matrix I, show that I² =I

n×n identity matrix is as shown in figure

Elements of identity matrix are

\delta I_{ij}=1\quad if\quad i=j\\\delta I_{ij}=0\quad if\quad i\ne j\\

As square of 1 is equal to 1 so for n×n identity matrix I, I² =I

(c) what do you think the enteries of Ik are?

As mentioned above

\delta I_{ij}=1\quad if\quad i=j\\\delta I_{ij}=0\quad if\quad i\ne j\\

Any power of 1 is equal to 1 so kth power of 1 is also 1. According to this Ik=I

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3 years ago
Vlad is playing on a swing set.
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Answer:

D(t)=-cos(3t)

Step-by-step explanation:

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