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skad [1K]
3 years ago
10

Why is it better to use deionized water in chemistry experiments

Chemistry
1 answer:
Leno4ka [110]3 years ago
6 0

Answer:

Laboratories use both distilled water and deionized water as controls in experiments. Deionization removes only non-charged organic matter from the water.

Explanation:

Distilled water removes even more impurities than deionization does, if the water undergoes a filtering process before boiling and distillation.

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What did Thomson’s model of the atom include that Dalton’s model did not have?
Allushta [10]
Thomson's model included Protons and Electrons. His model is referred to as 'Plum Pudding' because of it.
6 0
3 years ago
Read 2 more answers
If 16 moles of al react with 3 moles of S8 how many moles of Al2 S3 will be formed
Gnom [1K]

Answer:

8 moles

Explanation:

Al reacts with S_8 to produce Al_2S_3 as

Al+S_8\rightarrow Al_2S_3

The balanced chemical equation is

16Al+3S_8\rightarrow 8Al_2S_3

In the reaction, 16 moles of Al react with 3 moles of S_8 to produce 8 moles of Al_2S_3.

8 0
3 years ago
A scientist has 0.12 miles of a gas at a pressure of 4.06 kPa and a volume of 14 liters in an enclosed container. What is the te
natka813 [3]

Answer:

56972.17K

Explanation:

P = 4.06kPa = 4.06×10³Pa

V = 14L

n = 0.12 moles

R = 8.314J/Mol.K

T = ?

We need ideal gas equation to solve this question

From ideal gas equation,

PV = nRT

P = pressure of the ideal gas

V = volume the gas occupies

n = number of moles

R = ideal gas constant

T = temperature of the gas

PV = nRT

T = PV / nR

T = (4.06×10³ × 14) / (0.12 × 8.314)

T = 56840 / 0.99768

T = 56972.17K

Note : we have a large number for temperature because we converted the value of pressure from kPa to Pa

7 0
3 years ago
In a coffee-cup calorimeter, 1.55 g KOH is added to 125 ml of 0.80 M HCl. The following reaction occurs. KOH(s) + HCl(aq) → H2O(
DENIUS [597]

Answe1.55 gr:

Explanation:

yes

4 0
3 years ago
If the reaction N2 (g) + 3 H2 (g) --> 2 NH3 (g) has the concentrations 1.1 M for nitrogen, 0.75 M for hydrogen and 0.25 M fo
Luba_88 [7]

<u>Answer:</u> The value of K_c is 0.136 and is reactant favored.

<u>Explanation:</u>

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{c}

For the chemical reaction between carbon monoxide and hydrogen follows the equation:

N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)

The expression for the K_{c} is given as:

K_{c}=\frac{[NH_3]^2}{[N_2][H_2]^3}

We are given:

[NH_3]=0.25M

[H_2]=0.75M

[N_2]=1.1M

Putting values in above equation, we get:

K_c=\frac{(0.25)^2}{1.1\times (0.75)^3}

K_c=0.135

There are 3 conditions:

  • When K_{c}>1; the reaction is product favored.
  • When K_{c}; the reaction is reactant favored.
  • When K_{c}=1; the reaction is in equilibrium.

For the given reaction, the value of K_c is less than 1. Thus, the reaction is reactant favored.

Hence, the value of K_c is 0.136 and is reactant favored.

4 0
3 years ago
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