Explanation:
It is given that,
Mass of the soccer ball, m = 0.425 kg
Speed of the ball, u = 15 m/s
Angle with horizontal, 
Time for which the player's foot is in contact with it, 
Part A,
The x component of the soccer ball's change in momentum is given by :



The y component of the soccer ball's change in momentum is given by :



Hence, this is the required solution.
Given:
u(initial velocity)=0
a=5.54m/s^2
v(final velocity)=2 m/s
v=u +at
Where v is the final velocity.
u is the initial velocity
a is the acceleration.
t is the time
2=0+5.54t
t=2/5.54
t=0.36 sec
Answer:
0.34
Explanation:
2.5 Mg = 2500 kg
The change in speed from 100 km/h to 40 km/h is

The deceleration caused by friction force is the change in speed per unit of time

Using Newton 2nd law we can calculate the friction force that caused this deceleration:
F = ma = 2500 * 3.33 = 8333 N
Let g = 9.8m/s2. Friction force is the product of normal (gravity) force and friction coefficient


Answer:12.5 W
Explanation:
work = force * distance
175 J = 25N * d
d = 7 meters ◄
power = work / time
P = 175J / 14s = 12.5 W ◄