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Marysya12 [62]
3 years ago
12

How are h2o and NaCL different

Chemistry
1 answer:
MAVERICK [17]3 years ago
3 0

Answer:

1. H2O is a covalent bond, NaCl is an ionic bond

2. H2O uses hydrogen bonding (H-bonds), NaCl does not

3. H2O is liquid at room temperature. NaCl is solid.

Explanation:

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If mixture didn't exist how would life be different​
ollegr [7]

Answer:

boring

Explanation:

life would be meaningless like everyone being like on person

8 0
3 years ago
Using a molar heat of combustion of hexane (C6H14) –4163 kJ/mol, the mass of hexane required to increase the temperature of 1.76
pshichka [43]

Answer:

7.46 g.

Explanation:

  • Firstly, we need to calculate the amount of heat needed to warm 5.64 kg of water from 21.0°C to 70.0°C using the relation:

<em>Q = m.c.ΔT,</em>

where, Q is the amount of heat absorbed by water (Q = ??? J).

m is the mass of water <u><em>(m: we will determine).</em></u>

c is the specific heat capacity of water (c = 4.186 J/g.°C).

ΔT is the temperature difference (final T - initial T) (ΔT =  70.0 °C - 21.0 °C = 49.0 °C).

  • To determine the mass of 1.76 L of water we can use the relation:

mass = density x volume.

density of water = 1000 g/L & V = 1.76 L.

∴ mass = density x volume = (1000 g/L)(1.76 L) = 1760.0 g.

∵ Q = m.c.ΔT

<em>∴ Q = m.c.ΔT </em>= (1760.0 g)(4.186 J/g.°C)(49.0 °C) = 360483.2 J ≅ 360.4832 kJ.

  • As mentioned in the problem the molar heat of combustion of hexane is - 4163.0 kJ/mol.

<em>Using cross multiplication we can get the no. of moles of hexane that are needed to be burned to release 360.4832 kJ:</em>

Combustion of 1.0 mole of methane releases → - 4163.0 kJ.

Combustion of ??? mole of methane releases → - 360.4832 kJ.

∴ The no. of moles of hexane that are needed to be burned to release 360.4832 kJ = (- 360.4832 kJ)(1.0 mol)/(- 4163.0 kJ) = 0.0866 mol.

  • Now, we can get the mass of hexane that must be burned to warm 1.76 L of water from 21.0°C to 70.0°C:

<em>∴ mass = (no. of moles needed)(molar mass of hexane)</em> = (0.0866 mol)(86.18  g/mol) = <em>7.46 g.</em>

5 0
3 years ago
The southernmost point of india is _____
Oxana [17]

Answer:

<h2><em><u>(a) indra point</u></em></h2>

Explanation:

Indira point is the southern most point of India and is situated on great nicobar island in the nicobar island.

8 0
3 years ago
Read 2 more answers
A 1,900-m3 water tower has been cleaned with a chlorine solution. The vapors of chlorine in the tower exceed allowable concentra
yaroslaw [1]

Answer:

t = 1862 s

Explanation:

To do this, we need first to determine the theorical detention time, which can be determined with the following expression:

t₀ = ∀/Q  (1)

Where:

t₀: detention time

∀: Volume of the fluid in the reactor

Q: Flow rate in the reactor

With this time, we must use the following expression to determine the time that the workers will take to vent the tank:

C = C₀ e^(-t/t₀)   (2)

From here, we must solve for time t, and the expression will be:

t = ln(C₀/C) * t₀   (3)

Now that we know the expression to use, let's solve for t. Using (1) to determine the detention time, ∀ is 1900 m³, and Q is 2.35 m³/s so:

t₀ = 1900 / 2.35 = 808.51 s

Now, let's solve for the time t. C will be 0.0015 mg/L (or 1.5 mg/m³ cause in 1 m³ we have 1000 L) and C₀ 15 mg/m³:

t = ln(15/1.5) * 808.51

<h2>t = 1861.66 s or simply 1862 s</h2><h2></h2>

Hope this helps

6 0
3 years ago
If light at 193 nm from an argon–fluoride laser is incident on a gold metal surface, electrons with kinetic energy of 1.80  10–
MAVERICK [17]

Answer:work function= 8.2×10-19J

Minimum wavelength of light required= 2.4×10-7m

Explanation:

The wavelength of incident light was given as 193nm. We have to convert this to meters and have 193×10-9m. Then we use it to find the energy of incident photon E. When E is found we now apply Einstein photoelectric equation to obtain the work function Wo since the kinetic energy of photoelectrons is known as 1.8×10-19J.

From this work function. We can obtain the minimum wavelength of light required. All these steps are shown in the image attached.

3 0
3 years ago
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