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Serggg [28]
3 years ago
10

A football player runs down a field with a speed of 8 m/s. How long will it take him to run 20m?

Physics
2 answers:
Shtirlitz [24]3 years ago
5 0
To find the answer for this question, you simply need to divide 20 by 8, which is the speed he is traveling. 

20 / 8 = 2.5

The football player will run 20 yards in 2 1/2 seconds.
Hope that helped! =)
Charra [1.4K]3 years ago
3 0

Answer:

Time taken, t = 2.5 seconds

Explanation:

It is given that,

Speed of the football player, v = 8 m/s

We have to find time taken by the football player to run 20 m. It can be calculated suing the formula of speed of the player i.e.

s=\dfrac{d}{t}

d = distance

t = time taken

t=\dfrac{d}{s}

t=\dfrac{20\ m}{8\ m/s}

t = 2.5 seconds

Hence, time taken by the football player is 2.5 seconds

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A satellite is in a circular orbit 8200 km above the Earth’s surface; i.e., it moves on a circular path under the influence of n
andreyandreev [35.5K]

Answer:

5.23km/s

Explanation:

Given

Radius of Earth = 6.37 * 10^6 m

Altitude of Satellite = 8200km = 8200 * 10³m = 8.2 * 10^6 m

Gravity Acceleration on Satellite Altitude = 1.87965m/s²

For a satellite to remain in circular orbit, then it means the acceleration of gravity must be exact as the centripetal acceleration.

Centripetal Acceleration = V²/R

So, Acceleration of Gravity (A)= Centripetal Acceleration = V²/R

Make V the subject of formula

A = V²/R

V² = AR

V = √AR

Where R = (radius of earth) + (altitude of satellite)

R = 6.37 * 10^6 + 8.2 * 10^6

R = 14.57 * 10^6m

A = 1.87965m/s²

V = √(1.87965 * 14.57x10^6)

V = √27386500.5

V = 5233.211299001789

V = 5233.2113 m/s ------- Approximated

V = 5.23km/s

7 0
3 years ago
A brass alloy is known to have a yield strength of 240 MPa (35,000 psi), a tensile strength of 310 MPa (45,000 psi), and an elas
Karo-lina-s [1.5K]

Answer:

Here Strain due to testing is greater than the strain due to yielding that is why computation of load is not possible.

Explanation:

Given that

Yield strength ,Sy= 240 MPa

Tensile strength = 310 MPa

Elastic modulus ,E= 110 GPa

L=380 mm

ΔL = 1.9 mm

Lets find strain:

Case 1 :

Strain due to elongation (testing)

ε = ΔL/L

ε = 1.9/380

ε = 0.005

Case 2 :

Strain due to yielding

\varepsilon' =\dfrac{S_y}{E}

\varepsilon' =\dfrac{240}{110\times 1000}

ε '=0.0021

Here Strain due to testing is greater than the strain due to yielding that is why computation of load is not possible.

For computation of load strain due to testing should be less than the strain due to yielding.

4 0
3 years ago
The position of a full moon is located
marissa [1.9K]

Answer:

opposite the sun. between the Earth and the sun. rising perpendicular to the sun.

Explanation:

4 0
3 years ago
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A clothes dryer in a home draws a current of 10 amps when connected on a special 220-volts household circuit.what is the resista
aliya0001 [1]

Answer:

22Ω

Explanation:

if    V ⇒ voltage

      I ⇒ current

      R ⇒ resistance

V = IR

220 = 10 x R

220 / 10 = R

22 = R

8 0
2 years ago
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n200080 [17]
Fnet=F1+F2 or Fnet=F1-F2
So 400n up - 600n down
Fnet= 400-600= -200N
5 0
3 years ago
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