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azamat
2 years ago
11

A 0.750-kg object hanging from a vertical spring is observed to oscillate with a period of 1.50 s. When the 0.750-kg object is r

emoved and replaced by a 1.50-kg object, what will be the period of oscillation
Physics
1 answer:
lawyer [7]2 years ago
3 0

Answer:

New time period, T_2=2.12\ s

Explanation:

Given that,

Mass of the object 1, m_1=0.75\ kg

Time period, T_1=1.5\ s

If object 1 is replaced by object 2, m_2=1.5\ kg

Let T_2 is the new period of oscillation.

The time period of oscillation of mass 1 is given by :

T_1=2\pi \sqrt{\dfrac{m_1}{k}}

1.5=2\pi \sqrt{\dfrac{0.75}{k}}............(1)

The time period of oscillation of mass 2 is given by :

T_2=2\pi \sqrt{\dfrac{m_2}{k}}

T_2=2\pi \sqrt{\dfrac{1.5}{k}}............(2)

From equation (1) and (2) we get :

(\dfrac{T_1}{T_2})^2=\dfrac{m_1}{m_2}

(\dfrac{1.5}{T_2})^2=\dfrac{0.75}{1.5}

\dfrac{1.5}{T_2}=0.707

T_2=2.12\ s

So, the new period of oscillation is 2.12 seconds. Hence, this is the required solution.

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Nataly_w [17]

Answer:

0.092 m

Explanation:

A charged moving particle immersed in a region with magnetic field follows a circular trajectory at constant speed (uniform circular motion), since the magnetic forces acts perpendicular to the direction of motion of the particle.

Since the magnetic force acts as centripetal force, we can write:

qvB=m\frac{v^2}{r}

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v is its velocity

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Solving the equation for r,

r=\frac{mv}{qB}

For the ion of oxygen-16, we have:

m_A=2.66\cdot 10^{-26}kg

q_A = 1.6\cdot 10^{-19}C (it is singly charged)

v_A=2.90\cdot 10^6 m/s

B_A=1.30 T

So the radius of its orbit is

r_A=\frac{m_A v_A}{q_A B_A}=\frac{(2.66\cdot 10^{-26})(2.90\cdot 10^6)}{(1.6\cdot 10^{-19})(1.30)}=0.371 m

For the ion of oxygen-18, we have:

m_B = \frac{18}{16}m_A = 2.99\cdot 10^{-26}kg

q_B = 1.6\cdot 10^{-19}C (it is singly charged)

v_B=2.90\cdot 10^6 m/s

B_B=1.30 T

So the radius of its orbit is

r_B=\frac{m_B v_B}{q_B B_B}=\frac{(2.99\cdot 10^{-26})(2.90\cdot 10^6)}{(1.6\cdot 10^{-19})(1.30)}=0.417 m

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d=2(r_B-r_A)=2(0.417-0.371)=0.092 m

3 0
2 years ago
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6 0
3 years ago
a student in your class says "electromagnetic waves can travel through outer space but mechanical waves can’t.” is it this stude
Kitty [74]

Answer:

Right

Explanation:

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7 0
2 years ago
A circus acrobat is shot out of a cannon with an initial upward speed of 34 ft/s. if the acrobat leaves the cannon 4 ft above th
jok3333 [9.3K]
<h2>It will take 0.125 seconds to reach the net.</h2>

Explanation:

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Substituting

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              4.905t² - 10.36 t + 1.22 = 0

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Minimum time is 0.125 seconds.

It will take 0.125 seconds to reach the net.

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