Explanation:
From the given parameters we can calculate the mass and number of moles in this amount of solution of NaCl
Volume of solution = 1L
Molarity = 0.5M
We know that this is a solution. The molarity indicates that amount of solute was dissolved in a solvent.
To find the number of moles of solution;
Number of moles = molarity x volume
molarity is the the number of moles of solute in a solution.
input the variables;
Number of moles = 0.5 x 1 = 0.5moles
Mass of NaCl:
Mass of NaCl = number of moles x molar mass
molar mass of NaCl = 58.54g/mol
Mass of NaCl = 0.5 x 58.54 = 29.27g
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Answer:
Released into the atmosphere
Explanation:
The carbon that the plant had been storing when it was alive, would be released upon death into the soil
Atomic number is the number of protons in an atom. Since these are all Hydrogen, the number of protons remains the same, and the Atomic Number for each is 1. Mass number is the number of Protons and Neutrons in an atom. So, Protium is 1, Deuterium is 2, Tritium is 3. The number of neutrons is stated in the question (Protium 0, Deuterium 1, Tritium 2). Hope this helps, if you wouldn’t mind marking brandies if it did!
Answer:
0.316 moles are produced.
Explanation:
We state the redox reaction:
4HNO₃ + Cu → Cu(NO₃)₂ + 2NO₂ + 2H₂O
We need to determine the limting reactant:
0.1 L . 14 M = 1.4 moles
10 g . 1mol/ 63.54g =0.158 mol
Cu is the limiting reactant. Let's see
4 moles of acid need 1 mol of Cu to react
1.4 moles of acid may react to (4 . 1) / 1.4 = 0.35 moles
We do not have enough Cu.
1 mol of Cu can produce 1 mol of NO₂
Then 0.158 moles will produce, 0.316 moles. (double of moles)
If we see stoichiometry, ratio is 1:2
Answer:
pH = 8.18
Explanation:
The weak base, X, reacts with HCl as follows:
X + HCl → HX⁺ + Cl⁻
<em>Where 1 mole of X with 1 mole of HCl produce 1 mole of HX⁺ (The conjugate acid of the weak base).</em>
Now, using H-H equation for bases:
pOH = pKb + log [XH⁺] / [X]
<em>Where pOH is the pOH of the buffer (pH = 14 -pOH)</em>
<em>pKb is -log Kb = 5.824</em>
<em>And [X] [HX⁺] are the molar concentrations of each specie</em>
Now, at the neutralization of the half of HX⁺, the other half is as X, that means:
[X] = [HX⁺]
And:
pOH = pKb + log [HX⁺] / [X]
pOH = 5.824 + log 1
pOH = 5.824
pH = 14-pOH
<h3>pH = 8.18</h3>
