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3 years ago

16. A small piece of silver was placed in a solution containing both magnesium nitrate and copper(II) nitrate.

1 answer:

3 0

I believe it's about the dislodging response as Ag structures solvent salt with nitrate. For dislodging response, more receptive metal will uproot less receptive metal from the arrangement. In your question, the reactivity of the metal are positioned as takes after: Mg > Cu > Ag. Take note of that more responsive metals, that are Mg and Cu, are in the arrangement.

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Mutations _______ have a positive effect on an organism

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3 years ago

What is the mass of 5.26 mol Fe2(SO4)3?<br> Answer in units of g.

dsp73

<h3>Answer:</h3>

2100 g Fe₂(SO₄)₃

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Stoichiometry</u>

Using Dimensional Analysis

<u>Atomic Structure</u>

Reading a Periodic Table

<h3>Explanation:</h3>

<u>Step 1: Define</u>

5.26 mol Fe₂(SO₄)₃

<u>Step 2: Identify Conversions</u>

Molar Mass of Fe - 55.85 g/mol

Molar Mass of S - 32.07 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Fe₂(SO₄)₃ - 2(55.85) + 3(32.07) + 12(16.00) = 399.91 g/mol

<u>Step 3: Convert</u>

Set up: $\displaystyle 5.26 \ mol \ Fe_2(SO_4)_3(\frac{399.91 \ g \ Fe_2(SO_4)_3}{1 \ mol \ Fe_2(SO_4)_3})$
Multiply/Divide: $\displaystyle 2103.53 \ g \ Fe_2(SO_4)_3$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

2103.53 g Fe₂(SO₄)₃ ≈ 2100 g Fe₂(SO₄)₃

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vlada-n [284]

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