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diamong [38]
3 years ago
5

A shipment of sugar fills 4 1/3 containers. If each container holds 2 1/7 tons of sugar, what is the amount of sugar in the enti

re shipment?
Write your answer as a mixed number in simplest form.
Mathematics
2 answers:
mr Goodwill [35]3 years ago
5 0

The entire shipment contains 9 2/7 tons of sugar

Step-by-step explanation:

  • Step 1: Find the total amount of sugar in the entire shipment.

Number of containers in the shipment = 4 1/3 = 13/3

Number of tons of sugar = 2 1/7 = 15/7

⇒ Total amount of sugar = 13/3 × 15/7 = 65/7 = 9 2/7 tons

Sergeeva-Olga [200]3 years ago
4 0

To find the answer we need multiply the number of containers by number tons of sugar each container has.

(4 1/3 )*(2 1/7).

To calculate , we need to convert mixed numbers into improper fractions.

4 1/3 = (4*3 +1)/3 = 13/3

2 1/7 = (2*7+1)/7 =15/7

(4 1/3 )*(2 1/7) = (13/3) * (15/7) = (13*5)/7 = 65/7 = 9 2/7 (tons)

Answer: 9 2/7 tons.

Hope this helps!

~*`Testtaker01`*~

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Answer:

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Step-by-step explanation:

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\dfrac{810+x}{x}=\dfrac{100}{10},\\ \\10(810+x)=100x,\\ \\8100+10x=100x,\\ \\100x-10x=8100,\\ \\90x=8100,\\ \\x=\dfrac{8100}{90}=90\ g.

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