Start with the 19.7 mol HNO3. use dimensional analysis to correctly convert from mol HNO3 to gram H2O. so, it should look similar to 19.7 mol HNO3 x (2 mol H2O/6 mol HNO3) x (18 g H2O/1 mol H2O)
the first parenthesis’ numbers were received from the balanced equation (for every 6 mol HNO3, 2 mol H2O formed). the second is converting from moles to grams by using the molar mass of H2O (1+1+16). you should get 709.2/6. once you divide those, the answer should be 118.2 g H2O. I’m not sure if your computer requires you to use the exact answer or stop at the correct number of significant digits, but if it does then it might just be 118. g H2O.
The problem can solved using the heat equation which is expressed as:
H = mCΔT
where H is the energy absorbed or released, m is the mass of the substance, C is the specific heat capacity, and ΔT is the change in temperature.
2208 J = 41 g x 4.18 J/g·°C x ( T - 24 °C)
T = 36.88 °C
Answer:
Explanation:
Total moles = 300 + 500 = 800 moles
mole fraction of carbon dioxide = 300 / 800 = 3 / 8
water = 500 / 800 = 5 / 8
Total pressure = 21 atm
partial pressure of water = total pressure x mole fraction of water
= 21 x 5 / 8
= 13.125 atm
Answer:
3 electrons is contributed from each Nitrogen atom.
Total 6 electrons are shared in N₂.
Explanation:
- Nitrogen is belong to group VA
- it have 5 electron in its outer most Shell.
- it need 3 electrons complete its octet to become stable.
- Nitrogen have total 7 electrons.
- its atomic number is 7
The electronic configuration of Nitrogen is as:
1s², 2s², 2p³
it exist in diatomic form standard temperature and pressure.
Nitrogen form covalent bond and share 3 electron from each side.
total 6 electron are shared between 2 nitrogen atom.
For Covalent bonding it can share its 3 electrons.
The diagrammatic representation is in attachment.
So in order to answer this we need the number of moles of oxygen and the right stoichiometry.
The balanced reaction should be 2HgO --> 2Hg + O2, therefore 2 moles of mercury are produced for every one mole of oxygen gas. Since we have the mass of O2 we can calculate the moles as moles = mass/RMM where RMM is the relative molecular mass of O2, which is 32 g/mol. Therefore the number of moles = 125/16 = 3.9 mol.
Since 2 moles of Hg are produced for every one mole of O2, the number of moles of Hg = 3.9*2 = 7.8 mol.
