Complete the equation for respiration: Oxygen + ________ ---> carbon dioxide + energy + water *

A 11.0 mLmL sample of 0.30 MHBrMHBr solution is titrated with 0.16 MNaOHMNaOH. Part A What volume of NaOHNaOH is required to rea

cupoosta [38]

Answer:

21 mL of NaOH is required.

Explanation:

Balanced reaction: $HBr+NaOH\rightarrow NaBr+H_{2}O$

Number of moles of HBr in 11.0 mL of 0.30 M HBr solution

= $(\frac{0.30}{1000}\times 11.0)$ moles = 0.0033 moles

Let's say V mL of 0.16 M NaOH solution is required to reach equivalence point.

So, number of moles of NaOH in V mL of 0.16 M NaOH solution

= $(\frac{0.16}{1000}\times V)$ moles = 0.00016V moles

According to balanced equation-

1 mol of HBr is neutralized by 1 mol of NaOH

So, 0.0033 moles of HBr are neutralized by 0.0033 moles of NaOH

Hence, $0.00016V=0.0033$

$\Rightarrow V=\frac{0.0033}{0.00016}=21$

So, 21 mL of NaOH is required.

4 0

3 years ago

2. What do you think a

Monica [59]

Answer:

hey discover an

interesting pattern in the

world that no one else

has described, but they

cannot explain what is

causing the pattern?

Explanation:

3 0

2 years ago

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Why is there no overall electrical charge on an aluminium atom?

Alex787 [66]

The atoms always have an equal amount of protons and neutrons so lets say if one had 10 positive then it would have 10 negatives making it neutral.
10-10=0

3 0

3 years ago

Animals breathe oxygen and release carbon dioxide during cellular respiration according to the equation below. How much oxygen i

kifflom [539]

Answer:

14.544 g of oxygen is needed to produce 120 grams of carbon dioxide.

Explanation:

Animals take in oxygen and breathe out carbon dioxide during cellular respiration. The reaction for the metabolism of the food in the animal body is:

$C_6H_{12}O_6 + O_2 \rightarrow 6CO_2 + 6H_2O + Energy$

As can be seen from the reaction stoichiometry that:

6 moles of carbon dioxide gas can be produced from 1 mole of oxygen gas in the process of metabolism of glucose.

Also,

Given :

Mass of carbon dioxide gas = 120 g

Molar mass of carbon dioxide gas = 44 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus, moles of carbon dioxide are:

$moles_{CO_2} = \frac{120 g}{44 g/mol}$

$moles_{CO_2} = 2.7273 mol$

As mentioned:

6 moles of carbon dioxide gas can be produced from 1 mole of oxygen gas in the process of metabolism of glucose.

1 mole of carbon dioxide gas can be produced from 1/6 mole of oxygen gas in the process of metabolism of glucose.

2.7273 mole of carbon dioxide gas can be produced from $\frac{1}{6} \times 2.7273$ moles of oxygen gas in the process of metabolism of glucose.

Thus, moles of oxygen gas needed = 0.4545 moles

Molar mass of oxygen gas = 32 g/mol

The mass of oxygen gas can be find out by using mole formula as:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Mass\ of\ oxygen\ gas = Moles \times Molar mass}$

$Mass\ of\ oxygen\ gas = 0.4545 \times 32}$

$Mass\ of\ oxygen\ gas = 14.544 g$

14.544 g of oxygen is needed to produce 120 grams of carbon dioxide.

3 0

3 years ago

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The boundaries of a watershed are determined by

MrMuchimi

Answer: elevation , The boundaries of a watershed are determined by topography, which is the shape or the physical features of the land's surface. If the highest points of land surrounding a river were connected (like “connect-the-dots”), this line would form the watershed boundary.

7 0

3 years ago