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maksim [4K]
3 years ago
6

Complete the equation for respiration: Oxygen + ________ ---> carbon dioxide + energy + water *

Chemistry
1 answer:
Tom [10]3 years ago
5 0

Answer:Sunlight

Explanation:

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!!!! If you need more information just let me know.
e-lub [12.9K]
What basically your question is can you tell
8 0
3 years ago
What is the pH of the solution if the [H+] is 1 x 10-12 ?
jarptica [38.1K]

Answer:

<h2>12</h2>

Explanation:

The pH of a solution can be found by using the formula

pH = - log [ {H}^{+} ]

From the question we have

pH =  -  log(1 \times  {10}^{ - 12} )  \\

We have the final answer as

<h3>12</h3>

Hope this helps you

5 0
2 years ago
WHAT DOES THIS SAY AND WHAT THE ANSWER
notka56 [123]

It says

The majority of elements on the periodic table are ______________ (metals, nonmetals, or metalloids).  

The periodic table on the left separates elements into three groups: the metals (green in the table), nonmetals (orange), and metalloids (blue). Most elements are metals.

Apr 18, 2003

4 0
3 years ago
What are the reactants to burning paper and the products
posledela
<span>CO2 (carbon) is the main product that results from burning paper. The paper is the reactant When paper burns in a fire, the reactants are mostly carbon (the main substance in the paper) and oxygen (from the air).Co2 If paper is loaded with CaCO3 such as cigarette paper, CaCO3 decompose in to CaO and CO2</span>
3 0
2 years ago
How many acetate ions are formed when three formula units of zinc acetate dissociate?
jeyben [28]
A formula unit is the same as the empirical formula of a compound or an ionic molecule. It is the lowest ratio of the atoms in the compound or ion. Zinc acetate ions dissociates into zinc ions and acetate ions. The dissociation reaction is expressed as follows:
Zn(O2CCH3)2 = Zn2+ + 2(O2CCH3)1-

We determine the amount of acetate ions produced as follows:

Moles Zn(O2CCH3)2 = (3 formula units Zn(O2CCH3)2) ( 1 mol / 6.022x10^23 formula units) = 4.98x10^-24 mol Zn(O2CCH3)2
moles (O2CCH3)1- = 4.98x10^-24 mol Zn(O2CCH3)2 ( 2 mol (O2CCH3)1- / 1 mol Zn(O2CCH3)2 ) = 9.96x10^-24 mol (O2CCH3)1-
# of acetate ions = 9.96x10^-24 mol (O2CCH3)1- ( 6.022x10^23 ions / 1 mol (O2CCH3)1-) = 6 acetate ions
3 0
3 years ago
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