When an electron of a hydrogen atom travels from n = 4 to n = 2, a photon of energy 4.165 × 10-19 joules is released. Calculate
the wavelength associated with this radiation.
2 answers:
Answer:
4.77 × 10-7 meters
Explanation:
Energy of photon, E = hν
Frequency of photon,
Thus, energy of photon,
Therefore, 4.165 × 10-19 joules =
λ =
λ =
λ = 4.77 × 10-7 meters
The frequency of a photon having energy of 4.165 × 10-34 joules is 4.77 × 10-7 meters.
Answer:
Explanation:
please delete this it was a mistake
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