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lisabon 2012 [21]
3 years ago
14

When an electron of a hydrogen atom travels from n = 4 to n = 2, a photon of energy 4.165 × 10-19 joules is released. Calculate

the wavelength associated with this radiation.
Chemistry
2 answers:
Lesechka [4]3 years ago
8 0

Answer:

4.77 × 10-7 meters

Explanation:

Energy of photon, E = hν  

Frequency of photon,

Thus, energy of photon,

Therefore, 4.165 × 10-19 joules =

λ =

λ =

λ  = 4.77 × 10-7 meters

The frequency of a photon having energy of 4.165 × 10-34 joules is 4.77 × 10-7 meters.

gulaghasi [49]3 years ago
4 0

Answer:

Explanation:

please delete this it was a mistake

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3 years ago
1 point
Elina [12.6K]

Answer:

84672 J

Explanation:

From the question given above, the following data were obtained:

Height (h) = 72 m

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E = 120 × 9.8 × 72

E = 84672 J

Thus, the energy is 84672 J

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