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VMariaS [17]
3 years ago
6

What kind of graph is this?

Chemistry
2 answers:
stepan [7]3 years ago
8 0
It is a bar graph! First person who answered was correct!!
Novosadov [1.4K]3 years ago
3 0
That is a bar graph.
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Which oneof the following would best be measured useing kilometers
Alex
A. the distance between towns
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3 years ago
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Given the following information: benzoic acid = C6H5COOH hydrocyanic acid = HCN C6H5COOH is a stronger acid than HCN (1) Write t
Maurinko [17]

Answer:

The net ionic equation is

C6H5COOH+ CN-= C6H5COO- + HCN

Explanation:

From the ionic equation

C6H5COOH + Na+ + CN- = C6H5COO- + Na+ + HCN

Only sodium is the spectator ion, so it cancels out, since C6H5COOH and HCN do not ionize completely they are left undissociated

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3 years ago
How does prairie grasses protect soil
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4 0
3 years ago
Now examine salts containing the halide anions, cl- and br-. Most of these are soluble. What two cations listed lead to insolubl
tatiyna

Ag+ and Pb+2 are two cations that are suggested as producing insoluble halide salts when studying salts containing the halide anions, cl- and br-. First, the charge's number is provided.

Neutral binary salts, also referred to as halide salts, are mixtures of metals and non-metals. The non-metal behaves in a reduced oxidation state at all times. They are the outcome of mixing a hydroxide and hydracid. halide salts of haloids are produced by the reaction of a hydroxide and a hydracid.

Ions are cations with positive charges. They emerge when the electrons of an elemental metal are lost. However, they don't lose any protons; they only lose one or more electrons. To denote a cation, the charge is superscripted following the element name or chemical formula.

Learn more about halide salts here

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8 0
1 year ago
When a 1.00 L sample of water from the surface of the Dead Sea (which is more than 400 meters below sea level and much saltier t
Harlamova29_29 [7]

Answer: Molarity of MgCl_2 in the original sample was 1.96M

Explanation:

Molarity is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{\text{no of moles}}{\text{Volume in L}}

{\text {moles of solute}=\frac{\text {given mass}}{\text {molar mass}}=\frac{186g}{95g/mol}=1.96

Now put all the given values in the formula of molarity, we get

Molarity=\frac{1.96}{1.00L}

Molarity=1.96mol/L

Thus molarity of MgCl_2 in the original sample was 1.96M

4 0
3 years ago
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