The problem is missing some parts but nevertheless here is
the answer:
Given:
1.7 m long barbell with 23 kg weight on the left and 34 in
the right end.
Solution:
Calculating from the left side:
Center of gravity = ΣM/ΣW = [23*0 + 9*(1.7/2) + 34*1.7]/[23+9+34]
Center of gravity = .992 m from the left end
The answer is "the same than the mercury in the bigger tube".
If one barometer tube has twice the cross-sectional area of another, mercury in the smaller tube will rise the same than the mercury in the bigger tube.
The mercury will rise to the point where the column of mercury has the same weight as the force exerted by the atmosphere.
The force exerted by the atmosphere is pressure * cross-sectional area
Anf the weight of the column of mercury, W, will be:
W = m* g
where m = density * volume, and volume = cross-sectional area * height
=> W = density * cross-sectional area * height
Then, you make W = F and get:
density * cross-sectional area * height = P * cross-sectional area
The term cress-sectional area appears on both sides so it gets cancelled, and the height of the column of mercury does not depend on the cross-sectional area of the barometer.
12.) Active transport because the cell must use energy to move large particles across the membrane.
13.) Photosynthesis takes place in plant leaves containing the chlorophyll pigment. Cellular respiration takes place in the cytoplasm and mitochondria of the cell. ... Cellular respiration uses glucose molecules and oxygen to produce ATP molecules and carbon dioxide as the by-product.
14.) In cells with a nucleus, as in eukaryotes, the cell cycle is also divided into two main stages: interphase and the mitotic (M) phase (including mitosis and cytokinesis). During interphase, the cell grows, accumulating nutrients needed for mitosis, and undergoes DNA replication preparing it for cell division.
