Ideal gas law:
PV=nRT ⇒ V=nRT / P
P=pressure=1 atm
V=volume
n=number moles=2.10 moles
R=0,082 Atm l/ºK mol
T=temperature=273 K

V=(2.10 moles*0.082 (atm l)/º(K mol)*237ºK) / 1 atm=47.01 litres

47.1 L

5 0

3 years ago

What volume in litres will 38gr of F2 occupy at 0.999 bar and 273 K

FrozenT [24]

Answer:

$V=22.68L$

Explanation:

Hello,

In this case, we use the ideal gas equation to compute the volume as shown below:

$PV=nRT\\\\V=\frac{nRT}{P}$

Nonetheless we are given mass, for that reason we must compute the moles of gaseous fluorine (molar mass: 38 g/mol) as shown below:

$n=38 g *\frac{x}{y} \frac{1mol}{38 g} =1mol$

Thus, we compute the volume with the proper ideal gas constant, R:

$V=\frac{1mol*0.083\frac{bar*L}{mol*K}*273K}{0.999bar} \\\\V=22.68L$

Best regards.

7 0

3 years ago