Answer:
![\frac{a_{r,earth}}{a_{r,mars}} = 2.325](https://tex.z-dn.net/?f=%5Cfrac%7Ba_%7Br%2Cearth%7D%7D%7Ba_%7Br%2Cmars%7D%7D%20%3D%202.325)
Explanation:
The distance of Earth from the Sun is
and of Mars from the Sun is
. Let assume that both planets have circular orbits. The centripetal accelaration can be found by using the following expression:
![a_{r} = \frac{v^{2}}{R}](https://tex.z-dn.net/?f=a_%7Br%7D%20%3D%20%5Cfrac%7Bv%5E%7B2%7D%7D%7BR%7D)
Since planet has translation at constant speed, this formula is applied to compute corresponding speeds:
![v=\frac{2\pi\cdot r}{\Delta t}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B2%5Cpi%5Ccdot%20r%7D%7B%5CDelta%20t%7D)
Earth:
![v_{earth} = \frac{2\pi\cdot (149.6\times 10^{9}\,m)}{(365\,days)\cdot(\frac{24\,hours}{1\,day} )\cdot(\frac{3600\,s}{1\,h} )}](https://tex.z-dn.net/?f=v_%7Bearth%7D%20%3D%20%5Cfrac%7B2%5Cpi%5Ccdot%20%28149.6%5Ctimes%2010%5E%7B9%7D%5C%2Cm%29%7D%7B%28365%5C%2Cdays%29%5Ccdot%28%5Cfrac%7B24%5C%2Chours%7D%7B1%5C%2Cday%7D%20%29%5Ccdot%28%5Cfrac%7B3600%5C%2Cs%7D%7B1%5C%2Ch%7D%20%29%7D)
![v_{earth}=29806.079\,\frac{m}{s}](https://tex.z-dn.net/?f=v_%7Bearth%7D%3D29806.079%5C%2C%5Cfrac%7Bm%7D%7Bs%7D)
Mars:
![v_{mars} = \frac{2\pi\cdot (227.9\times 10^{9}\,m)}{(687\,days)\cdot(\frac{24\,hours}{1\,day} )\cdot(\frac{3600\,s}{1\,h} )}](https://tex.z-dn.net/?f=v_%7Bmars%7D%20%3D%20%5Cfrac%7B2%5Cpi%5Ccdot%20%28227.9%5Ctimes%2010%5E%7B9%7D%5C%2Cm%29%7D%7B%28687%5C%2Cdays%29%5Ccdot%28%5Cfrac%7B24%5C%2Chours%7D%7B1%5C%2Cday%7D%20%29%5Ccdot%28%5Cfrac%7B3600%5C%2Cs%7D%7B1%5C%2Ch%7D%20%29%7D)
![v_{mars}=24124.244\,\frac{m}{s}](https://tex.z-dn.net/?f=v_%7Bmars%7D%3D24124.244%5C%2C%5Cfrac%7Bm%7D%7Bs%7D)
Now, centripetal accelarations can be found:
Earth:
![a_{r,earth} = \frac{(29806.079\,\frac{m}{s} )^{2}}{149.6\times 10^{9}\,m}](https://tex.z-dn.net/?f=a_%7Br%2Cearth%7D%20%3D%20%5Cfrac%7B%2829806.079%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%29%5E%7B2%7D%7D%7B149.6%5Ctimes%2010%5E%7B9%7D%5C%2Cm%7D)
![a_{r,earth} = 5.939\times 10^{-3}\,\frac{m}{s^{2}}](https://tex.z-dn.net/?f=a_%7Br%2Cearth%7D%20%3D%205.939%5Ctimes%2010%5E%7B-3%7D%5C%2C%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D)
Mars:
![a_{r,mars} = \frac{(24124.244\,\frac{m}{s} )^{2}}{227.9\times 10^{9}\,m}](https://tex.z-dn.net/?f=a_%7Br%2Cmars%7D%20%3D%20%5Cfrac%7B%2824124.244%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%29%5E%7B2%7D%7D%7B227.9%5Ctimes%2010%5E%7B9%7D%5C%2Cm%7D)
![a_{r,mars} = 2.554\times 10^{-3}\,\frac{m}{s^{2}}](https://tex.z-dn.net/?f=a_%7Br%2Cmars%7D%20%3D%202.554%5Ctimes%2010%5E%7B-3%7D%5C%2C%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D)
The ratio of Earth's centripetal acceleration to Mars's centripetal acceleration is:
![\frac{a_{r,earth}}{a_{r,mars}} = \frac{5.939}{2.554}](https://tex.z-dn.net/?f=%5Cfrac%7Ba_%7Br%2Cearth%7D%7D%7Ba_%7Br%2Cmars%7D%7D%20%3D%20%5Cfrac%7B5.939%7D%7B2.554%7D)
![\frac{a_{r,earth}}{a_{r,mars}} = 2.325](https://tex.z-dn.net/?f=%5Cfrac%7Ba_%7Br%2Cearth%7D%7D%7Ba_%7Br%2Cmars%7D%7D%20%3D%202.325)
Answer:
0.0016 T
Explanation:
Parameters given:
Diameter of wire = 5 mm = 0.005 m
Radius of wire, R = 0.0025 m
Number of turns, N = 200
Current through the wire, I = 0.10A
The magnitude of the magnetic field is given as:
B = (u₀NI) / (2πR)
Where u = magnetic permeability of free space.
B = (1.257 * 10⁻⁶ * 200 * 0.1) / (2 * π * 0.0025)
B = 0.0016 T
The magnitude of the Magnetic field is 0.0016 T.
Explanation:
As we know that relation between energy and wavelength is as follows.
E = ![\frac{hc}{\lambda}](https://tex.z-dn.net/?f=%5Cfrac%7Bhc%7D%7B%5Clambda%7D)
This means that energy is inversely proportional to wavelength. So, more is the energy of an electromagnetic radiation less will be its wavelength.
Also, f = ![\frac{c}{\lambda}](https://tex.z-dn.net/?f=%5Cfrac%7Bc%7D%7B%5Clambda%7D)
Hence, less will be the wavelength more will frequency of a radiation.
Gamma rays are the rays that have highest energy, small wavelength and highest frequency.
Thus, we can conclude that gamma rays are the electromagnetic radiation which has the highest frequency.
1/20.... Frequency and period are inverses so whatever frequency is, period is one over that number. And versa visa
If you double the velocity of an object, its momentum doubles. but for the same increase in velocity, the kinetic energy increases 4 times..