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3 years ago

What do you mean by the statement relative density of gold is 19.3

1 answer:

8 0

The relative density of gold is 19.3 it means the ratio obtained by dividing the density of gold by water at temp of 4 degree celcius is 19.3

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The students on the right are applying a force of 100 N to the right. This is shown by the red arrow. The students on the left a

emmasim [6.3K]

Answer:

Explanation:

The rope will move left since there will be more force pulling on that side.

Hope it helps:)

8 0

1 year ago

Read 2 more answers

An underground tunnel has two openings, with one opening a few meters higher than the other. If air moves past the higher openin

klasskru [66]

Answer:

There would be a pressure drop in the direction of the higher opening. This will force air to move in from the lower opening and force it to leave through the higher opening. This will create a convectional movement of air, cooling and ventilating the tunnel.

Explanation:

This is in accordance with bernoulli's law of fluid flow which states that the pressure exerted by a moving fluid is lesser than it would exert if it were at rest.

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3 years ago

A capacitor of cylindrical shape as shown in the red outline, few cm long carries a uniformly distributed charge of 7.2 uC per m

Natali [406]

(a) The magnitude of the electric field at point 5.5m is 2.35 x 10⁴ N/C.

(b) The magnitude of the electric field at point 2.5m is 5.18 x 10⁴ N/C.

<h3>Electric field at a point on the Gaussian surface</h3>

The magnitude of the electric field at a point on the cylindrical Gaussian surface is calculated as follows;

E = λ/2πε₀r

where;

λ is linear charge density
ε₀ is permitivity of free space
r is the position of the charge

<h3>At a distance of 5.5 m</h3>

$E = \frac{\lambda}{2\pi \varepsilon _0 r} \\\\E = \frac{7.2 \times 10^{-6}}{2\pi \times 8.85 \times 10^{-12} \times 5.5} \\\\E = 2.35 \times 10^4 \ N/C$

<h3>At a distance of 2.5 m</h3>

$E = \frac{\lambda}{2\pi \varepsilon _0 r} \\\\E = \frac{7.2 \times 10^{-6}}{2\pi \times 8.85 \times 10^{-12} \times 2.5} \\\\E = 5.18 \times 10^4 \ N/C$

Thus, the magnitude of the electric field at points of 5.5m is 2.35 x 10⁴ N/C, and the magnitude of the electric field at points of 2.5m is 5.18 x 10⁴ N/C.

Learn more about electric field here: brainly.com/question/14372859

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2 years ago

Which is a better conductor, metal or non metal

sweet [91]

Metal would be a better conductor cause electricity can travel easier through it

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3 years ago

A 74 KG student starting from rest slides down 11.8 m high water slide how fast is it going at the bottom of the slide?

-Dominant- [34]

the answer is going to be 873.2

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3 years ago