Question

To a stationary observer, a bus moves north with a speed of 10 m/s. A man inside walks toward the back of the bus with a speed of 0.4 m/s relative to the bus. What is the velocity of the man according to a stationary observer?

Answer 1

Answer:

v = 9.6 m/s

Explanation:

Here we know that velocity is bus is

$v = 10 m/s$

also the person inside the bus is moving in opposite direction with repect to bus at speed of 0.4 m/s

now we know that

$\vec v_{12} = \vec v_1 - \vec v_2$

now we know that

$\vec v_{12} = -0.4 m/s$

$v_1 = ?$

$v_2 = 10 m/s$

now we have

$-0.4 = v_1 - 10$

$v_1 = 9.6 m/s$

so velocity of man is 9.6 m/s in direction of bus with respect to stationary observer

Answer 2

9.6m/s - apex .........................