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Brrunno [24]
3 years ago
14

What is his angular displacement during a 1.0 s time interval?

Physics
1 answer:
Leviafan [203]3 years ago
8 0

Answer:

The angular velocity is: (2π radians) ⁄ (4.3 sec) = 1.461 rad/sec

The angular displacement is: (1.461 rad/sec)(1 sec) = 1.461 radians

Explanation:

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velocity of ship with respect to water = 6.5 m/s due north

\overrightarrow{v}_{s,w}=6.5 \widehat{j}

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\overrightarrow{v}_{w,e}=1.5\left ( Cos40\widehat{i} +Sin40\widehat{j}\right)

velocity of ship with respect to water = velocity of ship with respect to earth - velocity of water with respect to earth

\overrightarrow{v}_{s,w} = \overrightarrow{v}_{s,e} - \overrightarrow{v}_{w,e}

\overrightarrow{v}_{s,e} = 6.5 \widehat{j}- 1.5\left (Cos40\widehat{i} +Sin40\widehat{j}  \right )

\overrightarrow{v}_{s,e} = - 1.15 \widehat{i}+5.54\widehat{j}

The magnitude of the velocity of ship relative to earth is \sqrt{1.15^{2}+5.54^{2}} = 5.66 m/s

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