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mel-nik [20]
3 years ago
5

Qual e sua idade cgreg

Physics
1 answer:
kozerog [31]3 years ago
3 0

I don't understand this, sorry!

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A particle travels along a straight line with a velocity v = (12 - 3t) m/s, where t is in seconds. When t = 1 s, the particle is
Simora [160]

Answer:

(1).The acceleration is -24 m/s²

The total distance is 912 m.

(2). The distance traveled before it stop is 78 m.

Explanation:

Given that,

Velocity = (12-3t^2) m/s

When t = 1 s, the particle is located 10 m to the left of the origin.

We need to calculate the acceleration at t = 4 sec

Using formula of acceleration

a=\dfrac{dv}{dt}

Put the value of v

a=\dfrac{d}{dt}(12-3t^2)

a=-6t

Put the value of t

a=-6\times4

a=-24\ m/s^2

The displacement from t = 0,t = 10 s, and the distance the particle travels during this time period.

We need to calculate the distance

Using formula of distance

ds=v\ dt

\int_{-10}^{s}=\int_{1}^{t}{v}dt

Put the value of v

\int_{-10}^{s}=\int_{1}^{t}{ (12-3t^2)}dt

s+10=12t-t^3-11

s=12t-t^3-21

At t = 0,

s_{t=0}=-21

At t = 10,

s_{t=10}=12\times10-10^3-21

s_{t=10}=-901

The displacement is

\Delta s=-901-(-21)

\Delta s=-880\ m

The distance at t= 2 sec

s_{t=2}=12\times2-2^3-21

s_{t=2}=-5

The total distance will be,

s_{T}=(21-5)+(901-5)

s_{T}=912\ m

(2). We need to calculate the distance at 2 sec

Using equation of motion

s=ut-\dfrac{1}{2}at^2

Put the value into the formula

s=27\times 2+\dfrac{1}{2}\times6\times(2)^3

s=78\ m

Hence, (1).The acceleration is -24 m/s²

The total distance is 912 m.

(2). The distance traveled before it stop is 78 m.

3 0
3 years ago
THE LENGTH OF A PENDULUM IS (1.5±0.01)m AND THE ACCELERATION DUE TO GRAVITY IS TAKEN AS (9.8±0.1)ms-² calculate the time period
tiny-mole [99]

Answer:

  2.4583 ± 0.0207 seconds

Explanation:

The time period of a pendulum is approximately given by the formula ...

  T = 2π√(L/g)

The maximum period will be achieved when length is longest and gravity is smallest:

  Tmax = 2π√(1.51/9.7) ≈ 2.47903 . . . seconds

The minimum period will be achieved for the opposite conditions: minimum length and maximum gravity:

  Tmin = 2π√(1.49/9.9) ≈ 2.43756 . . . seconds

If we want to express the uncertainty using a symmetrical range, we need to find half their sum and half their difference.

  T = (2.47903 +2.43756)/2 ± (2.47903 -2.43756)/2

  T ≈ 2.4583 ± 0.0207 . . . seconds

__

We have about 2+ significant digits in the given parameters, so the time might be rounded to 2.46±0.02 seconds.

5 0
3 years ago
Classify:Energyis the ability to exert force and cause change. Energy has manyforms:
Grace [21]

Answer:

Energy: Kinetic, Sound, Thermal, gravitational, electric, light and nuclear

Explanation:

This exercise asks to clarify a little some important concepts

* Energy. It is the capable one that has the bodies to carry out a job.

* Kinetic energy. It is the energy due to the movement of objects

* sound energy. It is the energy due to the vibration of the atoms or molecules of the materials, it can be solid, liquid or gaseous

* Thermal energy. It is the energy due to movement of the particles

* Gravitational Energy. It is a configuration energy due to the height of the bodies with respect to a reference point

* Electric power. It is due to the movement of electric charges

* light energy. It is the energy that light carries due to the electric and magnetic fields that form it, it occurs throughout the electromagnetic spectrum

* Nuclear energy. It is the energy stored in the nucleus by the configuration and movement of protons and neutrons.

6 0
3 years ago
How would improvement in use of renewable energy sources impact climate change sea-level rise?
bonufazy [111]

Answer:

Almost immeasurably small.

Explanation:

The STORY is that humans are BAD for the environment and have caused a HUGE change in the amount of CO₂ in the atmosphere.

Let's look at the reports and draw our own conclusions.

Current CO₂ levels are 409.8 parts per million (PPM)

at the beginning of the Industrial revolution in the 1700's, the presumed beginning of the huge increase in CO₂ the level was about 280 PPM

For perspective lets assume we capture the whole atmosphere and squish it down to 2400 one liter bottles of air

That's 100 cases of 24 bottles per case.

We now separate all the air components into their own bottles

Nitrogen is 78% of our air, so we subtract 78 cases from our 100 leaving 22

Subtracting Oxygen at 21% of air leaves 1 case of liter bottles left

Of those 24 bottles, Argon makes up 0.93% of air so we subtract 22 bottles

The remaining two bottles contain all of the other gasses in our air, One of those bottles contains CO₂.

If we take the CO₂ levels from the 1700's at about 280 PPM as a baseline and assume ALL of the increase is human caused, that is (410 -280) / 280 = 46 % of the total.

The human caused addition of CO₂ would be 460 mililiters out of 2400 liters over the course of 250 years 

The claim is, that less than half of a liter of CO₂ out of 2400 liters of air is responsible for heating not only the gas in all the other bottles but also the surface of the earth itself.

Personally, it boggles my mind.

And it says NOTHING of a far more powerful greenhouse gas that is far more prevalent in the atmosphere...water vapor.

Water vapor is about 1% of air at sea level and about 0.4% overall. It was not considered in the above analysis because water vapor can condense out and is not a constant in the air.

Notice that there is about 100 times the amount of water vapor in the air as compared to CO₂. Water vapor also has between 4 and 8 times the greenhouse effect that CO₂ does.

Makes one wonder why we choose to pick on CO₂.

7 0
3 years ago
The induced magnetic field at radial distance 4.0 mm from the central axis of a circular parallel-plate capacitor is 1.8 ✕ 10−7
wel

Answer:

\frac{dE}{dt}=2.07*10^{13}\frac{V/m}{s}

Explanation:

According to Gauss's law, the electric flux through the circular plates is defined as the electric field multiplied by its area:

\Phi=EA=E(\pi R^2)(1)

The magnetic field around the varying electric field of the circular plates is given by:

B=\frac{\epsilon_0 \mu_o}{2\pi r}\frac{d\Phi}{dt}(2)

Replacing (1) in (2) and solving for \frac{dE}{dt}:

B=\frac{\epsilon_0 \mu_o\pi R^2}{2\pi r}\frac{dE}{dt}\\\frac{dE}{dt}=\frac{2rB}{\epsilon_0 \mu_o R^2}\\\frac{dE}{dt}=\frac{2(4*10^{-3}m)(1.8*10^{-7}T)}{(8.85*10^{-12}\frac{C^2}{N\cdot m^2})(4\pi *10{-7}\frac{Tm}{A})(2.5*10^{-3}m)^2}\\\\\frac{dE}{dt}=2.07*10^{13}\frac{V/m}{s}

3 0
3 years ago
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