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mel-nik [20]
3 years ago
5

Qual e sua idade cgreg

Physics
1 answer:
kozerog [31]3 years ago
3 0

I don't understand this, sorry!

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The diagram shows two dodgeballs colliding. The red arrow shows the direction of force of the moving ball striking a stationary
Helen [10]

Answer:

The second arrow from the top to the bottom

Explanation:

This can be explained by the Newton's third law.

For every action there is an equal and opposite reaction.

When an object A exert a force to an object B. Then object B also excerts a force with the same size but opposite direction to object A.

5 0
4 years ago
Read 2 more answers
A ball is dropped from the top of a 77 m building. With what speed does the ball hit the ground? _________ m/s
vitfil [10]

Answer:

38.87 m/s

Explanation:

Given that the ball is dropped from a height = 77 m

u = 0 m/s

s = 77 m

a = g = 9.81 m/s²

Applying the expression as:

v^2-u^2=2as

Applying values as:

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 9.81\times 77+0^2}\\\Rightarrow v=38.87\ m/s

<u>The speed with which the ball hit the ground = 38.87 m/s</u>

3 0
3 years ago
The current theory of the structure of the
irina1246 [14]

Answer:

pt 1: m=1.66698*10^{21} kg

Pt 2: KE=1212.23531 J

Explanation:

Information Given: (p = density)

l = 5200km  d = 35km p = 2700kg/m^{2}

Part 1: Mass

  • Find volume
  1. V=(l)^2(d)
  2. V=(4.2*10^6)^2(35*10^3)
  3. V=61.74*10^{16}
  • Find Mass
  1. m=Vp
  2. m=(61.74*10^{16})(2700)
  3. m=1.66698*10^{21}

Part 2: Kinetic Energy

  1. v=\frac{3.8cm}{yr}*\frac{m}{100cm}*\frac{yr}{365d}*\frac{d}{24hr}*\frac{hr}{3600s}
  2. v=1.20497*10^{-9}

KE=\frac{1}{2}mv^2

KE=\frac{1}{2} (1.66698*10^{21})(1.20497*10^{-9})^2

KE=1212.23531 J

Part 3: Jogger Speed

set up, because I don't have the mass :(

Information given:

KE_{jogger}

  1. KE=\frac{1}{2}mv^2
  2. v_{jogger} =\sqrt{\frac{2KE}{m_{jogger} } }
  • Input the values

Hope it helps :)

6 0
3 years ago
A guitar string produces 3 beats/s when sounded with a 352-hz tuning fork and 8 beats/s when sounded with a 357-hz tuning fork.
MA_775_DIABLO [31]

Explanation:

The fluctuating sound heard when two objects vibrate with different frequencies is called beats. It is given that guitar string produces 3 beats/s when sounded with a 352 Hz tuning fork and 8 beats/s when sounded with a 357 Hz tuning fork.

It is assumed to find the vibrational frequency of the string.

For 3 beats/s, beat frequency can be :

352 - 3 or 352 + 3 = 349 Hz or 355 Hz

For 8 beats/s, beat frequency can be :

357 - 8 or 357 + 8 = 349 Hz or 365 Hz

It means that the vibrational frequency is 349 Hz.

5 0
4 years ago
How do you divide 5 km by 2 hours?
aleksandr82 [10.1K]

                    5 km  /  2 hrs

               =   (5/2)  (km/hr)

               =      2.5 km/hr .  
7 0
3 years ago
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