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bazaltina [42]
3 years ago
14

A 1.044 g sample contains only vitamin C (C6H8O6) and sucralose (C12H19Cl3O8). When the sample is dissolved in water to a total

volume of 33.0 mL, the osmotic pressure of the solution is 3.69 atm at 295 K. What is the mass percent of vitamin C and sucralose in the sample?​
Chemistry
2 answers:
ELEN [110]3 years ago
8 0

Answer:

blablablablablabla blablablablablabla

Strike441 [17]3 years ago
5 0

Answer:

1.044 g sample contains only vitamin C (C6H8O6) and sucralose (C12H19Cl3O8). When the sample is dissolved in water to a total volume of 33.0 mL, the osmotic pressure of the solution is 3.69 atm at 295 K.

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How many liters of carbon dioxide will 0.5 moles of lithium hydroxide (LiOH) absorb?
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Answer : The volume of carbon dioxide will be, 5.6122 L

Solution : Given,

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First we have to calculate the mass of carbon dioxide.

The balanced reaction will be,

2LiOH+CO_2\rightarrow Li_2CO_3+H_2O

From the reaction we conclude that

As, 2 moles of LiOH absorbs 44 grams of carbon dioxide

So, 0.5 moles of LiOH absorbs \frac{0.5moles}{2moles}\times 44g=11 grams of carbon dioxide

Mass of carbon dioxide = 11 g

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Now we have to calculate the volume of carbon dioxide.

Density=\frac{Mass}{volume}

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3 years ago
Two 10g blocks, one of copper and one of iron, were heated from 300 K to 400K (a temperature difference of 100 K).
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1) 385 J

2) 450 J

Explanation:

1)

The amount of energy that must be absorbed by a certain substance in order to increase its temperature by \Delta T is given by the equation:

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m is the mass of the substance

C is its specific heat capacity

\Delta T is the increase in temperature of the substance

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m = 10 g is the mass

C=0.385 J/gK is the specific heat capacity of copper

\Delta T=400-300 = 100 K is the change in temperature

So, the energy absorbed by the block of copper is

Q=(10)(0.385)(100)=385 J

2)

Similarly for the block of iron, the energy absorbed by the iron is given by

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Here we have:

m = 10 g is the mass of the block

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\Delta T=400-300 = 100 K is the change in temperature

So, the energy absorbed by the block of iron is

Q=(10)(0.450)(100)=450 J

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