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2 years ago

Help plz https://brainly.com/question/25361301

Mathematics

1 answer:

otez555 [7]2 years ago

6 0

Answer:

what do you need help with

Step-by-step explanation:

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Convert the integral below to polar coordinates and evaluate the integral.

White raven [17]

I suppose the integral is

$\displaystyle\int_0^5\int_y^{\sqrt{25-y^2}} xy\,\mathrm dx\,\mathrm dy$

The integration region corresponds to a sector of a cirlce with radius 5 subtended by a central angle of π/4 rad. We can capture this region in polar coordinates by the set

$R=\left\{(r,\theta)\mid0\le r\le5,0\le\theta\le\dfrac\pi4\right\}$

Then $x=r\cos\theta$ , $y=r\sin\theta$ , and $\mathrm dx\,\mathrm dy=r\,\mathrm dr\,\mathrm d\theta$ . So the integral becomes

$\displaystyle\iint_Rxy\,\mathrm dx\,\mathrm dy=\int_0^{\pi/4}\int_0^5r^3\sin\theta\cos\theta\,\mathrm dr\,\mathrm d\theta=\frac{625}{16}$

7 0

3 years ago

(100 POINTS) Please help I'll give brainliest! Image attached.

Norma-Jean [14]

Area of base=1/2(2.8)(4.2)

2.8(2.1)
5.88in²

Volume:

Area of base×Height
5.88(7)
41.16in³

Area of base

6×1/2(7)(6.1)
3(7)(6.1)
128.1cm²

Volume:-

128.1(14)
1793.4cm³

4 0

2 years ago

Read 2 more answers

currently there are 20 female senators and 80 Male senators serving in Congress. what percent of current Congress people are fem

kherson [118]

20%, there are 100 people so you base each person as a percentage.

5 0

3 years ago

Prove the following equation has no solutions. 13t+6=12+13t

Alex73 [517]

13t-13t=0
so your left with
6=12
which is a false statement which makes this equation have no solutions

8 0

3 years ago

The following integral requires a preliminary step such as long division or a change of variables before using the method of par

shtirl [24]

Division yields

$\dfrac{x^4+7}{x^3+2x} = x-\dfrac{2x^2-7}{x^3+2x}$

Now for partial fractions: you're looking for constants a, b, and c such that

$\dfrac{2x^2-7}{x(x^2+2)} = \dfrac ax + \dfrac{bx+c}{x^2+2}$

$\implies 2x^2 - 7 = a(x^2+2) + (bx+c)x = (a+b)x^2+cx + 2a$

which gives a + b = 2, c = 0, and 2a = -7, so that a = -7/2 and b = 11/2. Then

$\dfrac{2x^2-7}{x(x^2+2)} = -\dfrac7{2x} + \dfrac{11x}{2(x^2+2)}$

Now, in the integral we get

$\displaystyle\int\frac{x^4+7}{x^3+2x}\,\mathrm dx = \int\left(x+\frac7{2x} - \frac{11x}{2(x^2+2)}\right)\,\mathrm dx$

The first two terms are trivial to integrate. For the third, substitute y = x ² + 2 and dy = 2x dx to get

$\displaystyle \int x\,\mathrm dx + \frac72\int\frac{\mathrm dx}x - \frac{11}4 \int\frac{\mathrm dy}y \\\\ =\displaystyle \frac{x^2}2+\frac72\ln|x|-\frac{11}4\ln|y| + C \\\\ =\displaystyle \boxed{\frac{x^2}2 + \frac72\ln|x| - \frac{11}4 \ln(x^2+2) + C}$

7 0

2 years ago