The ion is Al³⁺
mass number - number of neutrons= atomic number
27 - 14 = 13
Aluminum has an atomic number of 13, thus we know this is the metal in question. Also, because the aluminum has only 10 electrons, (3 less than a neutral atom of aluminum would have), its charge must be 3+
These answers dont make sense
1. the 2s2 orbital will give one of its electrons to the 2p5 orbital so the configuration would be 1s22s12p6 (2s1 is half filled and 2p6 is completely filled which is a much more stable configuration)
2. Neon does not need to ionize it is a noble gas
Answer:
13.28 mol.
Explanation:
- We can use the general law of ideal gas:<em> PV = nRT.</em>
where, P is the pressure of the gas in atm (P = 1.32 atm).
V is the volume of the gas in L (V = 242.0 L).
n is the no. of moles of the gas in mol (n = ??? mol).
R is the general gas constant (R = 0.0821 L.atm/mol.K).
T is the temperature of the gas in K (T = 20.0° + 273 = 293.0 K).
∴ n = PV/RT = (1.32 atm)(242.0 L)/(0.0821 L.atm/mol.K)(293.0 K) = 13.28 mol.
Answer:
The value of entropy change for the process 
Explanation:
Mass of the ideal gas = 0.0027 kilo mol
Initial volume 
= 4 L
Final volume 
= 6 L
Gas constant for this ideal gas ( R ) = 
Where 
= Universal gas constant = 8.314 
⇒ Gas constant R = 8.314 × 0.0027 = 0.0224 
Entropy change at constant temperature is given by,
Put all the values in above formula we get,
![dS = 0.0224 log _{e} [\frac{6}{4}]](https://tex.z-dn.net/?f=dS%20%3D%200.0224%20%20log%20_%7Be%7D%20%5B%5Cfrac%7B6%7D%7B4%7D%5D)
This is the value of entropy change for the process.
