CaO
Calcium reacts with oxygen to form calcium oxide. The chemical equation for this reaction is Ca + O2 → CaO.
Answer:
Explanation:
We shall apply Arrhenius equation which is given below .
![ln\frac{k_2}{k_1} = \frac{E_a}{R} [\frac{1}{T_1} -\frac{1}{T_2} ]](https://tex.z-dn.net/?f=ln%5Cfrac%7Bk_2%7D%7Bk_1%7D%20%3D%20%5Cfrac%7BE_a%7D%7BR%7D%20%5B%5Cfrac%7B1%7D%7BT_1%7D%20-%5Cfrac%7B1%7D%7BT_2%7D%20%5D)
K₂ and K₁ are rate constant at temperature T₂ and T₁ , Ea is activation energy .
Putting the given values
![ln\frac{5.9}{1} = \frac{39500}{8.3} [\frac{1}{298} -\frac{1}{T_2} ]](https://tex.z-dn.net/?f=ln%5Cfrac%7B5.9%7D%7B1%7D%20%3D%20%5Cfrac%7B39500%7D%7B8.3%7D%20%5B%5Cfrac%7B1%7D%7B298%7D%20-%5Cfrac%7B1%7D%7BT_2%7D%20%5D)
![.000373= [\frac{1}{298} -\frac{1}{T_2} ]](https://tex.z-dn.net/?f=.000373%3D%20%5B%5Cfrac%7B1%7D%7B298%7D%20-%5Cfrac%7B1%7D%7BT_2%7D%20%5D)
T₂ = 335.27 K
= 62.27 °C
Answer:
<em>Mass percent composition of K = mass contribution of K/molecular mass of K3Fe(CN)6 x 100% Mass percent composition of K = 117.30 g/mol/329.27 g/mol x 100% Mass percent composition of K = 0.3562 x 100% Mass percent composition of K = 35.62%</em>
