Question

A point charge of 5.0 x 10^-7 C moves to the right at 2.6 x 10^5 m/s in a magnetic field that is directed into the screen and has a field strength of 1.8 x 10^-2 T.
What is the magnitude of the magnetic force acting on the charge?

Answer 1

The magnitude of the magnetic force acting on the charge is 2.34×10⁻³ N.

What is magnetic force?

A magnetic force is the force that act in a magnetic field.

To calculate the magnetic force, we use the formula below.

Formula:

• F = qvB.........Equation 1

Where:

• F = magnetic force
• q = point charge
• v = Velocity of the the charge
• B = Field strength

From the question,

Given:

• q = 5.0×10⁻⁷ C
• v = 2.6×10⁵ m/s
• B = 1.8×10⁻² T

Substitute these values into equation 2

• F = (5.0×10⁻⁷)(2.6×10⁵)(1.8×10⁻²)
• F = 23.4×10⁻⁴
• F = 2.34×10⁻³ N

Hence, the magnitude of the magnetic force acting on the charge is 2.34×10⁻³ N.

Learn more about magnetic force here: brainly.com/question/2279150

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