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Anastaziya [24]
1 year ago
14

A descending elevator of mass 1,000 kg is uniformly decelerated to rest over a distance of 8 m by a cable in which the tension i

s 11,000 N. The speed v_1 of the elevator at the beginning of the 8 m descent is most nearly (A)4 m/s (B) 10 m/s (C) 13 m/s (D) 16 m/s E) 21 m/s
Physics
1 answer:
WARRIOR [948]1 year ago
6 0

The speed v_1 of the elevator at the beginning of the 8 m descent is most nearly 4 m/s.

The rate of change in the position of an object in any course. Speed is measured because of the ratio of distance to the time wherein the distance became included. Speed is a scalar amount because it has the handiest route and no significance.

Velocity can be the notion of the rate at which an object covers distance. A quick-moving object has a high speed and covers a notably big distance in a given amount of time, whilst a sluggish-shifting item covers a relatively small amount of distance in the same amount of time.

The primary unit or the S.I. unit of velocity is m/s or ms⁻¹.

Learn more about Speed here:-brainly.com/question/13943409

#SPJ4

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3 years ago
To check if a stovetop is hot, you place you hand near the top of the stove and feel that it is warm without touching it. You ca
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5 0
3 years ago
A missle is fired horizontally with an initial velocity of 45 m/s from the top of a building 75 m high.
NARA [144]

The horizontal range of the missile is b) 176 m

Explanation:

The motion of the missile is a projectile motion, so it consists of two independent motions:  

- A uniform motion with constant velocity along the horizontal direction  

- A uniformly accelerated motion with constant acceleration (equal to the acceleration of gravity) in the vertical-downward direction  

To find the time of flight of the missile, we study the vertical motion. We can use the following suvat equation:

s=u_y t+\frac{1}{2}at^2

where:

s = 75 m is the vertical displacement of the missile (the height of the building)

u_y=0 is the initial vertical velocity  (the missile is thrown horizontally)

t is the time of flight

a=g=9.8 m/s^2 is the acceleration of gravity

Solving for t, we find the time of flight:

t=\sqrt{\frac{2s}{g}}=\sqrt{\frac{2(75)}{9.8}}=3.91 s

This means that the missile takes 3.91 s to reach the ground.

Now we study the horizontal motion: the missile moves with a constant horizontal velocity of

v_x = 45 m/s

Therefore, the distance covered in a time t is

d=v_x t

and by substituting t = 3.91 s, we find the horizontal range of the missile:

d=(45)(3.91)=176 m

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

4 0
4 years ago
The voltage across the input terminals of a transformer is 120 V. The primary has 25 loops and the secondary has 50 loops. The v
saw5 [17]

Answer:

240 V

Explanation:

Vp = 120 V

Np = 25

Ns = 50

Vs = ?

Vs / Vp = Ns / Np

Vs / 120 = 50 / 25

Vs / 120 = 2

Vs = 240 V

5 0
3 years ago
If size of an image is 10 cm and the magnification produced by a mirror is +1, what will be the size of object?
olya-2409 [2.1K]

Answer:

h = 10 cm

Explanation:

The magnification produced by a mirror is given by :

m=\dfrac{h'}{h}

h' is the image size and h is the object size

We have, h = 10 cm, m = +1

So,

m=\dfrac{h'}{h}\\\\h=\dfrac{10}{1}\\\\h=10\ cm

So, the size off the object is same as that of the size of the image i.e. 10 cm.

3 0
3 years ago
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