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Anastaziya [24]
1 year ago
14

A descending elevator of mass 1,000 kg is uniformly decelerated to rest over a distance of 8 m by a cable in which the tension i

s 11,000 N. The speed v_1 of the elevator at the beginning of the 8 m descent is most nearly (A)4 m/s (B) 10 m/s (C) 13 m/s (D) 16 m/s E) 21 m/s
Physics
1 answer:
WARRIOR [948]1 year ago
6 0

The speed v_1 of the elevator at the beginning of the 8 m descent is most nearly 4 m/s.

The rate of change in the position of an object in any course. Speed is measured because of the ratio of distance to the time wherein the distance became included. Speed is a scalar amount because it has the handiest route and no significance.

Velocity can be the notion of the rate at which an object covers distance. A quick-moving object has a high speed and covers a notably big distance in a given amount of time, whilst a sluggish-shifting item covers a relatively small amount of distance in the same amount of time.

The primary unit or the S.I. unit of velocity is m/s or ms⁻¹.

Learn more about Speed here:-brainly.com/question/13943409

#SPJ4

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first \: positive \: charge = q1 = 20

1micro \: =   {1}^{ - 6}

1q = 20 \times 10 {}^{ - 6}

second \: charge = q2 = 100 \times 10 {}^{ - 6}

formula = f =  \frac{k \times q1 × q2}{d {}^{2} }

remember

k = 9 \times  {10}^{9}

change distance 150cm to 1.5m

putting values

f =\frac{9 \times 10 {}^{9} \times 20  \times 10 {}^{ - 6} \times 100 \times  {10}^{ - 6}   }{1.5 {}^{2} }

<h2 /><h3>answer </h3><h3><u>8</u><u>N</u></h3>
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Read 2 more answers
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