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Gnesinka [82]
3 years ago
5

A Boy can raise a load of 200N up to aheight of 2.5m in 15 seconds. calculate hispower​

Physics
1 answer:
shtirl [24]3 years ago
7 0

Explanation:

f=mg

=200×10

=200N

Now,

work done=df

25×200

=500J

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a high schooler who lives on the "5th" floor of an apartment complex dropped his phone off the balcony. If the balcony is 18.75
Airida [17]

Answer:

1.38 s

Explanation:

Use the free falling formula

T = √(L)/ g

T = √18.75/9.8

T = 1.38 s

7 0
3 years ago
Laser transmissions travel at a higher speed than the radio waves true or false
uranmaximum [27]
<span>False. Laser transmissions and radio waves are both forms of electromagnetic radiation. Both travel at approximately 3.00 x 10^8 meters per second. This is the case because wavelength and frequency are directly proportional to this value. Although laser light has a shorter wavelength than radio waves, it will travel at the same speed because the frequency will be greater.</span>
6 0
3 years ago
A 1100 kg car rounds a curve of radius 68 m banked at an angle of 16 degrees. If the car is traveling at 95 km/h, will a frictio
Mariulka [41]

Answer:

Yes. Towards the center. 8210 N.

Explanation:

Let's first investigate the free-body diagram of the car. The weight of the car has two components: x-direction: towards the center of the curve and y-direction: towards the ground. Note that the ground is not perpendicular to the surface of the Earth is inclined 16 degrees.

In order to find whether the car slides off the road, we should use Newton's Second Law in the direction of x: F = ma.

The net force is equal to F = \frac{mv^2}{R} = \frac{1100\times (26.3)^2}{68} = 1.1\times 10^4~N

Note that 95 km/h is equal to 26.3 m/s.

This is the centripetal force and equal to the x-component of the applied force.

F = mg\sin(16) = 1100(9.8)\sin(16) = 2.97\times10^3

As can be seen from above, the two forces are not equal to each other. This means that a friction force is needed towards the center of the curve.

The amount of the friction force should be 8.21\times 10^3~N

Qualitatively, on a banked curve, a car is thrown off the road if it is moving fast. However, if the road has enough friction, then the car stays on the road and move safely. Since the car intends to slide off the road, then the static friction between the tires and the road must be towards the center in order to keep the car in the road.

5 0
3 years ago
What is Aristotle famous for?
Mila [183]

Answer:

History

Explanation:

Im. Sorry. Im. Not. Much. Help

8 0
3 years ago
NEED HELP ASP<br> WILL GIVE POINTS OR WHATEVER
solniwko [45]

Answer:

you need to multiply the momentum and the mass

8 0
3 years ago
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