Answer:
a)The direction the frictional force will acts is in the positive x direction.
Explanation:
a)The direction the frictional force will acts is in the positive x direction
b)in the horizontal direction, the total force F(total) is equal to 4times the frictional force in the wheel.
F(total)=4f
''f'' is taken as the frictional force.
c)4times the normal force on each wheel minus the acceleration equals zero i.e 4N(wheel)-a=0
=4N(wheel)-mg=0
d) torque is the force that tends to bend rotation
ζ=rf
but acceleration=4×frictional force
cross multiply
f=ζ/r
f=ma/4
ma/4=ζ/r
a=4ζ/r
Answer:
3947.6 N
Explanation:
Centripetal Force: This is the force that tend to moves a body towards the center of a circle during circular motion.
The formula for centripetal force is
F = mω²r ........................ Equation 1
Where F = Centripetal force, ω = angular velocity, r = radius.
Where π = 3.1415
Given: m = 4 kg, ω = 0.5 rev/s = (0.5×2π) rad/s = 3.1415 rad/s, r = 100 m.
Substitute into equation 1
F = 4(3.1415)²(100)
F = 3947.6 N
Hence the centripetal force on the turbine blade = 3947.6 N
The answer I'm pretty sure is 3
The acceleration should be a gain of 2 km/h per second
Answer
i'm not 100% sure but 1764
Explanation:
Work done = gravitational potential energy
Gravitational potential energy = mass(kg) × height(m) × gravitational field strength(N/kg)
We can assume that the student is on earth so the gravitational field strength is 9.8N/kg
So work done = 60 × 3×9.8
=1764
(if you need help calculating power but if you do just divide your answer by 12 and you will get 147)
