Answer:
Velocity of truck will be 20.287 m /sec
Explanation:
We have given mass of the truck m = 4000 kg
Radius of the turn r = 70 m
Coefficient of friction 
Centripetal force is given 
And frictional force is equal to 
For body to be move these two forces must be equal
So 

He will be a pilot and he will fly the plane over bridges fewwww
The property that compares the mass of an object with its volume is density.
closed and unsecure circuit