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Monica [59]
2 years ago
6

1. What is wave motion

Physics
1 answer:
nadya68 [22]2 years ago
8 0
A wave is basically propagation of disturbances—that is, deviations from a state of rest or equilibrium—from place to place in a regular and organized way. Most familiar are surface waves on water, but both sound and light travel as wavelike disturbances, and the motion of all subatomic particles exhibits wavelike properties.
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Density= mass/volume
So the answer is 2g/ml
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3 years ago
Need help with a physics question.
Verdich [7]

QUESTION:

WHAT IS THE MAGNITUDE OF THE MAGNETIC FIELD AT RIGHT ANGLES TO THE PROTON'S PATH?

ANSWER:

=<em><u>☑</u></em><em><u> </u></em><em><u>2</u></em><em><u>.</u></em><em><u>4</u></em><em><u> </u></em><em><u>T</u></em>

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A good train took 7 hours to complete its journey. For the first 3 hours, it travelled an average speed of 186km/h. What was the
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I really hope this helps

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3 years ago
An electron is a negatively charged particle that has a charge of magnitude, e - 1.60 x 10-19 C. Which one of the following stat
Ivahew [28]

Answer:

The electric field is directed toward the electron and has a magnitude of E=\frac{ke}{r^{2} }.

Explanation:

An electric field is define as the surrounding of charges which exert a force on each other and this force can be attractive or repulsive depends on the charge.

In the given case electron is given and the magnitude of charge on electron is e=1.6\times 10^{-19}C

Electric field can be represented as,

E=\frac{kQ}{r^{2} }

Here, r is the distance between the point ande charge, k is the electric field constant and Q is the charge.

In the given question an electron is given so electric field will be,

E=\frac{ke}{r^{2} }

As we know that electric field start from the positive charge and vanish in the negative charge.

So, here the electric field will be E=\frac{ke}{r^{2} } and it is directed toward the electron because of negative charge on the electron.

6 0
3 years ago
Identical balls are dropped from the same initial height and bounce back to half the initial height. In Case 1, the ball bounces
Kitty [74]

Answer:

<em>1. c. Same in both</em>

<em>2. a. Case 1</em>

<em></em>

Explanation:

1. The balls are identical in all sense, which means that if they are dropped from the same height, they should posses the same kinetic energy just before they collide with either the concrete floor or the stretchy rubber. Also, since they reach the same height when they bounced of the concrete floor or the piece of stretchy rubber, it means that they posses the same amount of kinetic energy at this point. Since their kinetic energy at these two points are the same, and they have the same masses, then this means that their momenta at these two instances will also be equal. Since all these is true, then the change in the momentum of the balls between the instance just before hitting the concrete floor or the stretchy rubber material and the instant the ball just leave the floor or the stretchy material is the same for both.

2. The ball that falls on the concrete will experience the greatest force, since the time of impact is small, when compared to the time spent by the other ball in contact with the stretchy rubber material; which will stretch, thereby extending the time spent in contact between them.

7 0
3 years ago
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