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Paha777 [63]
3 years ago
13

How many different atoms are there in a compound? ​

Physics
2 answers:
yKpoI14uk [10]3 years ago
7 0

Answer:

2 or more atoms

Explanation:

yes yes yes yes yes yes yes yes

musickatia [10]3 years ago
6 0

Answer:

Two or more

Explanation:

It's mostly two but unique structures might compose of more than 2

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To overcome the problems that blur images and don't provide the best resolution from Earth, astronomers have started using flexi
schepotkina [342]

Answer:

adaptive optics

Explanation:

simple

3 0
3 years ago
A bug is 12 cm from the center of a turntable that is rotating with a frequency of 45 rev/min . What minimum coefficient frictio
Agata [3.3K]

Answer:

The minimum coefficient of friction is 0.27.

Explanation:

To solve this problem, start with identifying the forces at play here. First, the bug staying on the rotating turntable will be subject to the centripetal force constantly acting toward the center of the turntable (in absence of which the bug would leave the turntable in a straight line). Second, there is the force of friction due to which the bug can stick to the table. The friction force acts as an intermediary to enable the centripetal acceleration to happen.

Centripetal force is written as

F_c = m\frac{v^2}{r}

with v the linear velocity and r the radius of the turntable. We are not given v, but we can write it as

v = r\omega

with ω denoting the angular velocity, which we are given. With that, the above becomes:

F_c = m\frac{v^2}{r}=m\omega^2 r

Now, the friction force must be at least as much (in magnitude) as Fc. The coefficient (static) of friction μ must be large enough. How large?

F_r=\mu mg \geq m\omega^2 r = F_c\implies\\\mu \geq \frac{\omega^2 r}{g}

Let's plug in the numbers. The angular velocity should be in radians per second. We are given rev/min, which can be easily transformed by a factor 2pi/60:

\frac{1 rev}{1 min}\cdot\frac{\frac{2\pi rad}{rev}}{\frac{60s}{1 min}}=\frac{2\pi}{60}\frac{rad}{s}

and so 45 rev/min = 4.71 rad/s.

\mu \geq \frac{\omega^2 r}{g}=\frac{4.71^2\frac{1}{s^2}\cdot 0.12m}{9.8\frac{m}{s^2}}=0.27

A static coefficient of friction of at least be 0.27 must be present for the bug to continue enjoying the ride on the turntable.



3 0
3 years ago
A mass of 10kg is a point a on a table is moved to a point B.if the line joining A and is horizantal what is the done on the obj
IrinaK [193]

Answer:

work done on the object by gravitational force = 0 joules

Explanation:

work = force × displacement

force = mass × acceleration

so,

work = mass × acceleration × displacement

we know that mass= 10 kg , gravitational acceleration= 9.8 m/s^2

and displacement= 0 m since the object is not moving vertically.

so,

work = 10 × 9.8 × 0 = 0 joules

6 0
2 years ago
Read 2 more answers
A network engineer is subnetting the 10.0.240.0/20 network into smaller subnets. Each new subnet will contain between a minimum
Solnce55 [7]

Answer:255.255.255.224

Explanation:

/20 has a subnet mask of 255.255.240.0

We have 20 on bits for the network and 16 off bits for the host. Since the designer wants 20 to 30 hosts in each subnet we will be having 5 off bits for the host. Therefore we will be having a /27..

Which will be 255.255.255.224

7 0
4 years ago
Which simple machines combine to make scissors?
marysya [2.9K]
The right answer is A. I'm one lever and two wedges

Hope this helps
6 0
4 years ago
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