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zimovet [89]
3 years ago
14

Jody has a mass of 50 kilograms what is his weight on earth

Physics
2 answers:
WARRIOR [948]3 years ago
5 0

Answer:

Weight of body = 490 Newton

Explanation:

Mass of the body is the total amount of matter contained in the body but Weight of the body is the force exerted by gravity on the body. Weight of the body depends upon acceleration due to gravity of the planet.

Thus,

Weight = mass × acceleration due to gravity

W = mg

W = weight of the body

m = mass of the body

g = acceleration due to gravity

W = 50 × 9.8

W = 490 \frac{kg m}{s^{2}}

W = 490 Newton

Hence, weight of the body is 490 Newton.

Dahasolnce [82]3 years ago
4 0
50x9.7(gravity on earth)=485
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A wheel has a radius of 5.9 m. How far (path length) does a point on the circumference travel if the wheel is rotated through an
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Answer:

(a). The path length is 3.09 m at 30°.

(b). The path length is 188.4 m at 30 rad.

(c). The path length is 1111.5 m at 30 rev.

Explanation:

Given that,

Radius = 5.9 m

(a). Angle \theta=30°

We need to calculate the angle in radian

\theta=30\times\dfrac{\pi}{180}

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We need to calculate the path length

Using formula of path length

Path\ length =angle\times radius

Path\ length=0.523\times5.9

Path\ length =3.09\ m

(b). Angle = 30 rad

We need to calculate the path length

Path\ length=30\times5.9

Path\ length=177\ m

(c). Angle = 30 rev

We need to calculate the angle in rad

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\theta=188.4\ rad

We need to calculate the path length

Path\ length=188.4\times5.9

Path\ length =1111.56\ m

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2 years ago
A small space probe of mass 170 kg is launched from a spacecraft near Mars. It travels toward the surface of Mars, where it will
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Answer:

The change  in momentum is  \Delta p =   kg \cdot m/s      

Explanation:

From the question we are told that  

       The mass of the probe is  m = 170 kg

       The location of the prob at time t = 22.9 s is  A  =

       The  momentum at time  t = 22.9 s is  p = < 51000, -7000, 0> kg m/s

        The net force on the probe is  F =  N

Generally the change in momentum is mathematically represented as

              \Delta p = F * \Delta t

The initial time is   22.6 s

 The final time  is  22.9 s

             Substituting values  

           \Delta p =  * (22.9 - 22.6)

            \Delta p =  * (0.3)  

              \Delta p =   kg \cdot m/s        

 

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