The mass (g) of the original sample after decomposition is 8.3983 g.
A decomposition reaction can be described as a chemical reaction wherein one reactant breaks down into or extra merchandise.
explanation:
Reaction 2KClO₃ ⇒ 2KCl + 3O₂
moles 2 2 3
molar mass 122.55 74.55 32
Given, Mass of O₂ = 3.29g ⇒ moles of O₂
= (3.29/32) = 0.1028
3 moles of O₂ produced by 2 moles of KClO₃
Therefore, 0.1028 moles of O₂ produced by (2*0.1028/3) = 0.06853 moles of Kclo₃
Mass of KClo₃ in original sample is = moles * molar mass
= 0.06853 * 122.55
= 8.3983 g
A decomposition response occurs whilst one reactant breaks down into or extra merchandise. this may be represented through the general equation: XY → X+ Y. Examples of decomposition reactions consist of the breakdown of hydrogen peroxide to water and oxygen, and the breakdown of water to hydrogen and oxygen.
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Hey there!:
Answer : D
A water molecule can donate a proton to another water molecule, forming H3O⁺and OH⁻ in solution.
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Answer:
4.67 kg
Explanation:
Given data
- Dimensions of the lead sheet: 75.0 cm by 55.0 cm by 0.10 cm
- Density of lead: 11.3 g/cm³
Step 1: Calculate the volume of the sheet
The volume of the sheet is equal to the product of its dimensions.
Step 2: Calculate the mass of the sheet
The density (ρ) is equal to the mass divided by the volume.
Answer:
32.1 g
Explanation:
Step 1: Write the balanced combustion reaction
C₄H₁₀ + 6.5 O₂ ⇒ 4 CO₂ + 5 H₂O
Step 2: Calculate the moles corresponding to 97.4 g of CO₂
The molar mass of CO₂ is 44.01 g/mol.
97.4 g × 1 mol/44.01 g = 2.21 mol
Step 3: Calculate the moles of butane that produced 2.21 moles of carbon dioxide
The molar ratio of C₄H₁₀ to CO₂ is 1:4. The moles of C₄H₁₀ required are 1/4 × 2.21 mol = 0.553 mol
Step 4: Calculate the mass corresponding to 0.553 moles of C₄H₁₀
The molar mass of C₄H₁₀ is 58.12 g/mol.
0.553 mol × 58.12 g/mol = 32.1 g
