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iren2701 [21]
2 years ago
9

What is the most reactable element in periodic table​

Chemistry
2 answers:
Olenka [21]2 years ago
7 0

The sodium metal is the most reactive element in the periodic table.

<h3 /><h3>What is alkali metals?</h3>

Alkali metals are metals found in the group of 1 of the periodic table.

Examples of metals found in group 1 in decreasing order of reactivity;

  • Sodium
  • Potassium
  • Lithium

The most reactive element in periodic table​ is found in the group 1 of the periodic table and this element is sodium.

Thus, sodium metal is the most reactive element in the periodic table.

Learn more about reactivity of elements here: brainly.com/question/2029679

nadya68 [22]2 years ago
3 0

Answer:

sodium

Explanation:

Mark me as a brain list pls

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Answer:

14720000

Explanation:

1 kg = 1000000 mg

14.72 kg = 14.72 x 1000000

=14720000

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Calculate the mass of 5.3 moles of chloric acid (hcl03)
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If I did the math right .. it would be 84.46grams
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The moon is not visible during which phase
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Gaseous methane reacts with gaseous oxygen gas to produce gaseous carbon dioxide and gaseous water. If 2.59 g of water is produc
max2010maxim [7]

<u>Answer:</u> The percent yield of the water is 31.98 %

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For methane:</u>

Given mass of methane = 6.58 g

Molar mass of methane = 16 g/mol

Putting values in equation 1, we get:

\text{Moles of methane}=\frac{6.58g}{16g/mol}=0.411mol

  • <u>For oxygen gas:</u>

Given mass of oxygen gas = 14.4 g

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

\text{Moles of oxygen gas}=\frac{14.4g}{32g/mol}=0.45mol

The chemical equation for the combustion of methane is:

CH_4+2O_2\rightarrow CO_2+2H_2O

By Stoichiometry of the reaction:

2 moles of oxygen gas reacts with 1 mole of methane

So, 0.45 moles of oxygen gas will react with = \frac{1}{2}\times 0.45=0.225mol of methane

As, given amount of methane is more than the required amount. So, it is considered as an excess reagent.

Thus, oxygen gas is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction

2 moles of oxygen gas produces 2 moles of water

So, 0.45 moles of oxygen gas will produce = \frac{2}{2}\times 0.45=0.45 moles of water

  • Now, calculating the mass of water from equation 1, we get:

Molar mass of water = 18 g/mol

Moles of water = 0.45 moles

Putting values in equation 1, we get:

0.45mol=\frac{\text{Mass of water}}{18g/mol}\\\\\text{Mass of water}=(0.45mol\times 18g/mol)=8.1g

  • To calculate the percentage yield of water, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield of water = 2.59 g

Theoretical yield of water = 8.1 g

Putting values in above equation, we get:

\%\text{ yield of water}=\frac{2.59g}{8.1g}\times 100\\\\\% \text{yield of water}=31.98\%

Hence, the percent yield of the water is 31.98 %

4 0
3 years ago
What element is reduced in the following reaction?
riadik2000 [5.3K]
 the oxidation states of the elements before and after the reaction is;
Pb oxidation state changes from 0 to +2
SO₄²⁻ ion there's no change in the oxidation state during the reaction
Au oxidation state changes from +3 to 0
reduction reactions are when there's a decrease in the oxidation state of the species 
oxidation reactions are when theres an increase in the oxidation state of the species 
the element where there's a decrease in oxidation state is Au. 
Therefore Au gets reduced.
answer is B) Au
6 0
4 years ago
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