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3 years ago

Why do you keep moving forward when you slam on the brakes of your bike?

2 answers:

7 0

If you're going really really slow and you hit the brakes, you're going to stop almost instantly. When you're going faster, you've got your energy which is your body size so it takes energy to stop the bike. When you slam the brake you're trying to apply that energy to the wheels. Even if you lock them up so the wheels aren't spinning, you skid because friction is rubbing against the ground and that will be what eventually stops you.

If you have a wider tire, you're going to have more surface area hitting the ground and that will cause more friction so you will stop faster. If you have skinnier tires you will skid more so there are a bunch of different factors.

g100num [7]3 years ago

6 0

Because the act of braking is an example of negative acceleration.
Example: if the rate of braking was say 2 meters per second^2, and the starting velocity was 10 m/s, it would take 5 seconds to come to a stop(during those 5 seconds you would still be moving).

You might be interested in

The worker’s pull on the handle of the cart can best be described as a force having

777dan777 [17]

Answer:

both magnitude and direction

Explanation:

The worker's pull on the handle of the cart is best described as the force having both magnitude and direction.

This is a vector quantity
The force is channeled to move the cart in a specific direction.
Also, the pull on the cart can be quantified, and so it have magnitude.
Most physical properties either have magnitude or direction or both.

In this case, the worker is pulling the cart towards a specified direction.

Therefore, the fitting choice is both magnitude and direction.

8 0

4 years ago

An electrician must decide between 3 heaters. The wire that she is using is rated 15A maximum, anything beyond that is a fire ha

lutik1710 [3]

Use the formula: $P=IV$ , where P is power (watts), I is current (amperes) and V is potential difference (volts).

For the first heater:
$900W = I_{1}*120V$
$I_{1} = 7.5A$

For the second heater:
$1800W = I_{2}*120V$
$I_{2} = 15A$

For the third heater:
$3000W = I_{3}*240V$
$I_{3} = 12.5A$

6 0

3 years ago

In levelling, the following staff readings were observed involving an inverted staff, A = 2.915 and B = -2.028. What is the rise

salantis [7]

Answer:

The rise from A to B is 0.887

Solution:

As per the question:

The following reading of an inverted staff is given as:

A = 2.915

B = -2.028

Here, for inverted staff, the greater reading shows greater elevation and lesser reading shows lower elevation.

Thus

The rise from A to B is given as:

A - B = 2.915 - 2.028 = 0.887

8 0

3 years ago

A circular loop of radius r carries a current i. at what distance along the axis of the loop is the magnetic field one-half its

lana [24]

At r = 0.766 R the magnetic field intensity will be half of its value at the center of the current carrying loop.

We have a circular loop of radius ' r ' carrying current ' i '.

We have to find at what distance along the axis of the loop is the magnetic field one-half its value at the center of the loop.

<h3>What is the formula to calculate the Magnetic field intensity due to a current carrying circular loop at a point on its axis?</h3>

The formula to calculate the magnetic field intensity due to a current carrying ( i ) circular loop of radius ' R ' at a distance ' x ' on its axis is given by -

$B(x) = \frac{\mu_{o} iR^{2} }{2(x^{2} +R^{2})^{\frac{3}{2} } }$