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almond37 [142]
3 years ago
6

If you put positive energy and negative energy into a spiral tube like a corkscrew with a barrier so they could not meet, so the

y act like one pulls and the other pushes would this create a continuum
Physics
1 answer:
Aleksandr-060686 [28]3 years ago
3 0

There are no rules that describe how positive energy behaves
in the presence of negative energy, because there is no such
thing as negative energy. 

(Wellll ... in pop Psychology, perhaps, but not in any real science.)

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The tongue weight of a trailer should be what percent of the gross trailer weight rating
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Answer:

between 10 and 15 percent

Explanation:

How to put your load

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The safe trailer starts loading correctly. Uneven weight can affect steering, brakes and swing control.

In general, 60% of the weight of the load should be in the front half of the trailer and 40% in the rear half (unless the manufacturer indicates something different). When you place the load, you want it to be balanced from side to side, keeping the center of gravity near the ground and on the axle of the trailer.

-  Hold your load

After balancing the load, you must hold it in place. An untapped load can move when the vehicle is moving and cause trailer instability.

- Trailer weight

To avoid overloading the trailer, look for the recommended weight rating. It is located on the VIN plate in the trailer chassis, usually on the tongue. Confirm the Gross Vehicle Weight Classification (GVWR) before towing.

GVWR: is the total weight that the trailer can support, including its weight. You can also find this number as the Gross Trailer Weight (GTW). The weight of the tongue should be 10-15% of the GTW.

7 0
2 years ago
Which choice correctly ranks these items from smallest to largest?
Vera_Pavlovna [14]

Answer:

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Explanation:

6 0
3 years ago
Why do all objects above earth's surface have gravitational potential energy
gayaneshka [121]
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26. A transformer increases or decreases
uysha [10]

Answer:

Explanation:

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7 0
3 years ago
A gas occupies a volume of 1.0 m3 in a cylinder at a pressure of 120kPa. A piston compresses the gas until the volume is 0.25m3,
Hoochie [10]

Answer:

Approximately 480\; \rm kPa, assuming that this gas is an ideal gas.

Explanation:

  • Let V(\text{Initial}) and P(\text{Initial}) denote the volume and pressure of this gas before the compression.
  • Let V(\text{Final}) and P(\text{Final}) denote the volume and pressure of this gas after the compression.

By Boyle's Law, the pressure of a sealed ideal gas at constant temperature will be inversely proportional to its volume. Assume that this gas is ideal. By this ideal gas law:

\displaystyle \frac{P(\text{Final})}{P(\text{Initial})} = \frac{V(\text{Initial})}{V(\text{Final})}.

Note that in Boyle's Law, P is inversely proportional to V. Therefore, on the two sides of this equation, "final" and "initial" are on different sides of the fraction bar.

For this particular question:

  • V(\text{initial}) = 1.0\; \rm m^3.
  • P(\text{Initial}) = 120\; \rm kPa.
  • V(\text{final}) = 0.25\; \rm m^3.
  • The pressure after compression, P(\text{Final}), needs to be found.

Rearrange the equation to obtain:

\displaystyle P(\text{Final}) = \frac{V(\text{Initial})}{V(\text{Final})} \cdot P(\text{Initial}).

Before doing any calculation, think whether the pressure of this gas will go up or down. Since the gas is compressed, collisions between its particles and the container will become more frequent. Hence, the pressure of this gas should increase.

\begin{aligned}P(\text{Final}) &= \frac{V(\text{Initial})}{V(\text{Final})} \cdot P(\text{Initial})\\ &= \frac{1.0\; \rm m^{3}}{0.25\; \rm m^{3}} \times 120\; \rm kPa = 480\; \rm kPa\end{aligned}.

4 0
3 years ago
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