Answer: 0.66 V
Explanation:
Given
Magnetic field, B = 0.963 T
Instantaneous rare = 74.5 cm/s = 0.745 m/s
radius, r = 14.7 cm = 0.147 m
We will use the formula
emf = dΦ/dt
emf = d(BA)/dt
emf = d(Bπr²)/dt
if B is constant, then we can say
emf = Bπ d(r²)/dt on differentiating, we have,
emf = Bπ (2r dr/dt)
emf = 2πrB dr/dt substituting each values, we have
emf = 2 * 3.142 * 0.147 * 0.963 * 0.745
emf = 0.66 V
Therefore, the induced emf in the loop at that instant is 0.66 V
Answer:
Explanation:
Given
Ultimate shear strength 
thickness of steel Plate 
Cross-sectional 
suppose d is the diameter of cross-section
Shear area of circular cross-section
Shear Force 
Answer:
average force = 385,140 N
Explanation:
from the question we are given the following
mass (m) = 1800 kg
distance of fall (d) = 3 m
driven distance (l) = 14.4 cm = 0.144 m
acceleration due to gravity (g) = 9.8 m/s^{2}
work done = average force x driven distance.....equation 1
and
work done = change in kinetic energy + change in potential energy
work done = (0.5 x m x (v^{2} - u^{2})) + (m x g x (-d-l))
- Initial velocity (u) and final velocity (v) are zero because the pile driver is it rest before it moves to hit the pile and after hitting the pile.
- The changes in length for the potential energy are negative because the pile moves downward
we now have work done = (m x g x (-d-l))...equation 2
now equating the two equations for work done we have
average force x driven distance = (m x g x (-d-l))
average force x 0.144 = 1800 x 9.8 x (-3-0.144)
average force = (1800 x 9.8 x (-3-0.144)) ÷ 0.144
average force = 385,140 N
Explanation:
Resting potential is the static membrane potential of the dormant cells. It is opposite of the action potential or the graded membrane potential. Na+/K+ ATPase pumps helps offset the ion diffusion through leak channels on neurons and helps return the membrane potential to its resting voltage.
