1) Molar mass C5H12= 5*12 +1 *12=60+12=72 g/mol
2) 40g C5H12 * 1 mol C5H12/72 g C5H12 = 40/72 mol C5H12
3) C5H12 + 8O2 ------> 5CO2 + 6H2O
by reaction 1 mol 8 mol
from problem 40/72 mol x mol
x=(40/72) * 8/1=(40*8)/72=(40)/9 mol O2
4) M(O2)=2*16 g/mol =32 g/mol
5) (40)/9 mol O2 *(32 g O2/ 1 mol )=(40 * 32)/9 =142.2 g O2
The numbers that balance the following equation: 4NaCl + 2SO2 + H2O + O2 → Na2SO4 + 4HCl is 2, 1, 2.
BALANCING EQUATION:
- Balancing a chemical equation means to make sure that the number of atoms of each element on both sides of the equation are equal.
- According to this question, the following chemical reaction are given: 4NaCl + 2SO2 + H2O + O2 → Na2SO4 + 4HCl
- Some of the coefficients (numbers) have been placed there while some are missing. The equation that includes the missing coefficients (numbers) to balance the equation is:
4NaCl + 2SO2 + 2H2O + O2 → 2Na2SO4 + 4HCl
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Answer:sorry id ont known
Explanation:give m brianlest if you want
The molar volume of a gas at STP occupies <u>22.4 L.</u>
Option D
<u>Explanation:</u>
To find the volume of 1 mole of a gas at STP, we use the Ideal Gas Law. It is the general gas equation which gives the relation to the measurable quantities to an ideal gas as below,
P (pressure) × V (volume) = n (number of moles) × R (the gas constant) × T (temperature in Kelvin)
STP = 1 atm of pressure and 273 K for temperature
P = 1 atm
V = ?
n = 1 mole
R = 0.0821 atm L/mol K
T = 273 K
Using the equation,
By substituting the above values, in the equation,
V = 22.38 L
