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vaieri [72.5K]
2 years ago
9

Why is the path of totality of a total solar eclipse on Earth so narrow?

Physics
2 answers:
astraxan [27]2 years ago
3 0
Because it just it dndbsnsnsbsnsnsnsnsnsnsnsnsn
algol [13]2 years ago
3 0

Answer:Because of the relative sizes of the moon and sun and their relative distances from Earth,

Explanation:

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A feather is dropped on the moon from the height of 1.4m. The acceleration of gravity on the moon is 1.67ms-1. Determine the tim
Zinaida [17]

1.3s

Explanation:

Given parameters:

Height = 1.4m

Gravity on moon = 1.67ms⁻¹

Unknown:

Time for feather to fall = ?

Solution:

To solve this problem, we are going to use one of the motion equation that relates time, gravity and height.

    H = ut + \frac{1}{2} g t^{2}

Sine the body was dropped from rest, initial velocity is zero;

 H = height

  u = initial velocity

  t = time

  g = acceleration due to gravity

since u = 0;

H = \frac{1}{2} g t^{2}

 1.4 = \frac{1}{2} x 1.67 x t²

  t = 1.3s

learn more:

Gravity brainly.com/question/10934170

#learnwithBrainly

8 0
3 years ago
What is the value of work done on an object when a
tino4ka555 [31]
W = F * s
Here, F = 50 N
s = 15 m

Substitute their values, 
W = 50 * 15
W = 750 J

In short, Your Answer would be 750 Joules

Hope this helps!
7 0
3 years ago
Interactive Solution 22.25 offers some help for this problem. A copper rod is sliding on two conducting rails that make an angle
dalvyx [7]

Answer:

The magnitude of average EMF induced in triangle is 0.0637

Explanation:

Induced EMF = (change in Magnetic Flux Density x Area)/change in Time

EMF = - ΔΦ /Δt

=-Bdelta A/delta(t)\\=-B(1/2AC.BC)/delta(t)\\AC=Vdelta(t)\\BC=Vdelta(t)tan(theta)\\=-BV^2delta(t)tan(theta)/2\\EMF=0.0637V

7 0
4 years ago
Use what you know about mass and how you use it to calculate force in the following situation. If each washer has a mass of 4.9
Leto [7]

Answer:

E D G E N U I T Y

The first answer is 0.0098 kg

The second answer is 0.192 kg

Explanation:

3 0
4 years ago
Read 2 more answers
a toy dart gun has a spring with k=128 N/m. a kid pulls back on the spring with a 8.22 N force. how far does it stretch?(unit=m)
german

Answer:

0.064 m

Explanation:

When a spring is stretched/compressed, the force exerted in the spring is related to the elongation of the spring by the equation:

F=kx

where:

F is the force applied

k is the spring constant

x is the stretching/compression of the spring

In this problem, we have:

F=8.22 N is the force applied by the kid on the spring

k = 128 N/m is the spring constant

Solving for x, we find how far the spring stretches:

x=\frac{F}{k}=\frac{8.22}{128}=0.064 m

8 0
3 years ago
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