2 years ago

Given a table of values for the exponential function f(x) and a description of the

Physics

1 answer:

Elodia [21]2 years ago

5 0

Answer:its D

Explanation:

i did the test and got it right

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Note: the 2 in the answers are exponents

stiks02 [169]

Final speed after collision with the wall

$v_f = -0.4 m/s$

before collision the speed of ball initially

$v_i = 0.6 m/s$

time taken for the collision

$\Delta t = 0.2 s$

now as per the formula of acceleration we know that

$a = \frac{v_f - v_i}{\Delta t}$

now plug in all values in it

$a = \frac{-0.4 - 0.6}{0.2}$

$a = -5.0 m/s^2$

so acceleration is - 5 m/s/s for above situation

4 0

4 years ago

Match the bones with their common name.

mrs_skeptik [129]

1. clavicle = collarbone

2. vertebrae = backbone

3. scapula = shoulder blade

4. femur = thigh

5. humerus = upper arm

6. patella = kneecap

7. cranium = skull

8. tibia = lower leg

9. radius/ulna = forearm

10. phalanges = fingers/toes

7 0

3 years ago

Two cars leave Calgary at the same time, travelling in opposite directions. Their average speeds differ by 5 km/h. After 2 h, th

dimulka [17.4K]

Let the first car's average speed be x

The second car's speed would be x+5

$2(x+(x+5))=210$

$2x+5=105$

$2x=100$

$x=50$

So the speed of the slower car is 50mph, and the speed of the faster car is 55mph

8 0

3 years ago

Read 2 more answers

Enunciado del ejercicio n° 1

hoa [83]

Answer:

Explanation:

6 0

3 years ago

Canola oil is less dense than water, so it floats on water, but its index of refraction is 1.47, higher than that of water. When

kupik [55]

Answer:

therefore critical angle c= 69.79°

Explanation:

Canola oil is less dense than water, so it floats over water.

Given $n_{canola}= 1.47$

which is higher than that of water

refractive index of water $n_{water}=1.33$

to calculate critical angle of light going from the oil into water

we know that

$sinc= \frac{n_{water}}{n_{canola}}$

now putting values we get

$sinc= \frac{1.33}{1.47}$

c= $sin^{-1}(\frac{1.33}{1.47} )$

c=69.79°

therefore critical angle c= 69.79°

8 0

3 years ago