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GaryK [48]
2 years ago
11

The box is pushed to the left with 30 N of force, but does not move. What is the Friction Force?​

Physics
2 answers:
balu736 [363]2 years ago
7 0

Explanation:

<h2><u>ᎪꪀsωꫀᏒ</u></h2>

The formula is => Ff = μN or => Ff = μmg

μ is friction's cofficient & N is normal reaction

➪the box is pushed to left but doesn't move means the force if limiting friction is greater than applied force.

Andrews [41]2 years ago
5 0

However here coefficient of friction is not given so unable to calculate.

You can calculate it by below formula.

The formula given by

\\ \sf\longmapsto F_f=\mu N

Or

\\ \sf\longmapsto F_f=\mu mg

u is coefficient of friction

N is normal reaction.

Here..

box doesn't move means the force if limiting friction is greater than applied force.

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Vector A with arrow, which is directed along an x axis, is to be added to vector B with arrow, which has a magnitude of 5.5 m. T
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Answer:

Magnitude of vector A = 0.904

Explanation:

Vector A , which is directed along an x axis, that is

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Vector B , which has a magnitude of 5.5 m

                   \vec{B}=x_B\hat{i}+y_B\hat{j}

                   \sqrt{x_{B}^{2}+y_{B}^{2}}=5.5\\\\x_{B}^{2}+y_{B}^{2}=30.25

The sum is a third vector that is directed along the y axis, with a magnitude that is 6.0 times that of vector A                    \vec{A}+\vec{B}=6x_A\hat{j}\\\\x_A\hat{i}+x_B\hat{i}+y_B\hat{j}=6x_A\hat{j}

Comparing we will get

                  x_A=-x_B\\\\y_B=6x_A

Substituting in x_{B}^{2}+y_{B}^{2}=30.25

                  \left (-x_{A} \right )^{2}+\left (6x_{A} \right )^{2}=30.25\\\\37x_{A}^2=30.25\\\\x_{A}=0.904

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8 0
4 years ago
1. Describe what happens to the gravitational when you increase mass versus when you
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Answer:

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