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Digiron [165]
3 years ago
13

What is the molarity of 2 mol of calcium carbonate, CaCl2, dissolved in 1 L of solution?

Physics
1 answer:
Agata [3.3K]3 years ago
6 0

Answer:

2mol/L

Explanation:

Given parameters:

Number of moles of calcium carbonate = 2mol

Volume of solution = 1L

Unknown:

Molarity  = ?

Solution:

The molarity of a solution is the number of moles of solute dissolved or contained in a solution:

 Molarity  = \frac{number of moles }{volume }  

 Molarity  = \frac{2}{1}   = 2mol/L

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Two sources of light of wavelength 700 nm are 9 m away from a pinhole of diameter 1.2 mm. How far apart must the sources be for
Lelechka [254]

Answer:

The distance is  D  =  0.000712 \ m

Explanation:

From the question we are told that

    The wavelength of  the  light source is  \lambda  =  700 \ nm = 700 *10^{-9} \  m

     The distance from a pin hole is  x  =  9\ m

       The  diameter of the pin  hole is  d =  1.2 \ mm  =  0.0012 \ m

     

Generally the distance which the light source need to be in order for their diffraction patterns to be resolved by Rayleigh's criterion is

mathematically represented as

              D  =  \frac{1.22 \lambda }{d }

substituting values

             D  =  \frac{1.22 * 700 *10^{-9} }{ 0.0012 }

             D  =  0.000712 \ m

5 0
3 years ago
A car (mass of 830 kg) is sitting on a car lift in a shop (neglect the mass of the lift itself). While the car is being lifted u
OLEGan [10]
There are two force acting on an object that is being lifted. (1) the weight of the car, (2) the upward force. The difference of these force should be equal to the product of the mass and the acceleration. (This is the content of Newton's 2nd Law of Motion). If we let the lifting force be F,
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The value of F from the equation is 11288 N. 
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3 years ago
Why might scientists measure the mass of object rather than the weight of an object?
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a concrete slab 20 m long and weighing 400,000 N is supported by one pillar. A 19,600 N car is parked 8 meters from one end, whe
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let the distance of pillar is "r" from one end of the slab

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mg = 19600 N

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400,000(r - 10) = 19,600 (10 - 8)

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2. In the pendulum lab, the period (swing time) was O a. the independent variable O b.graphed on the vertical-axis O c.graphed o
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