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2 years ago

What is the molarity of 2 mol of calcium carbonate, CaCl2, dissolved in 1 L of solution?

Physics

1 answer:

Agata [3.3K]2 years ago

6 0

Answer:

2mol/L

Explanation:

Given parameters:

Number of moles of calcium carbonate = 2mol

Volume of solution = 1L

Unknown:

Molarity = ?

Solution:

The molarity of a solution is the number of moles of solute dissolved or contained in a solution:

Molarity = $\frac{number of moles }{volume }$

Molarity = $\frac{2}{1}$ = 2mol/L

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alexgriva [62]

Answer:

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2 years ago

In a "worst-case" design scenario, a 2000-kg elevator with broken cables is falling at 4.00 m/s when it first contacts a cushion

Fofino [41]

Answer:

Part a)

$v_f = 3.65 m/s$

Part b)

$a = - 4 m/s^2$

Explanation:

Part a)

As we know that the elevator is stopped while spring is compressed by x = 2 m

now we will have

$\frac{1}{2}kx^2 + F_f x - mgx = \frac{1}{2}mv^2$

$\frac{1}{2}k(2^2) + (17000)(2) - (2000\times 9.81\times 2) = \frac{1}{2}(2000)(4^2)$

$2k + 34000 - 39240 = 16000$

$k = 10620 N/m$

Now we have to find the speed when spring is compressed by x = 1

So again by work energy theorem

$W_g + W_f + W_{spring} = \frac{1}{2}m(v_f^2 - v_i^2)$

$2000(9.81)(1) - 17000(1) - \frac{1}{2}(10620)(1^2) = \frac{1}{2}(2000)(v_f^2 - 4^2)$

$-2.69 = v_f^2 - 16$

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Part b)

Net force on the elevator while spring is compressed by x = 1

$F_{net} = mg - kx - F_f$

$F_{net} = 2000(9.81) - (10620\times 1) - 17000$

$F_{net} = -8000 N$

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vichka [17]

Answer:

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1 year ago

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jarptica [38.1K]

Answer:

a) 633.39 J

b) 0.28

Explanation:

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Work done by friction = energy change of the player

= $\frac{1}{2} 67(4.35)^{2}$ = 633.9 J

b) Assuming the frictional force stays constant,

Work done by friction = Frictional force×distance

Frictional force = kinetic friction(μ)×normal reaction

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Combining these equations

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Answer:

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Explanation:

Right out of the textbook.

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3 years ago