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2 years ago

Classify each as either a solid a liquid or a gas at room temperature

Chemistry

1 answer:

LenKa [72]2 years ago

7 0

Answer:

air gas

diamond solid

copper solid

candle wax solid or melted would be liquid

Explanation:

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lesya692 [45]

On adding salt.....The boiling temperature increases.....

So ∆t= KB * molality
=O.52*(58/58)/4
= O.52*1/4
= 0.13
So increase is 100+.13=100.13°c

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2 years ago

Find the volume of an object that has a mass of 20g and density of 184 glcm

expeople1 [14]

Volume= Mass/ Density= 20/184
= 0.108 cubic cm

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3 years ago

[Rn] 7s25f6d4<br> Which element is denoted

Colt1911 [192]

Answer:

Explanation:

[Rn] 7s25f6d4

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3 years ago

A volume of 90.0 mLmL of aqueous potassium hydroxide (KOHKOH) was titrated against a standard solution of sulfuric acid (H2SO4H2

Alja [10]

Answer:

0.823 M was the molarity of the KOH solution.

Explanation:

$H_2SO_4+KOH\rightarrow K_2SO_4+2H_2O$ (Neutralization reaction)

To calculate the concentration of base , we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_2SO_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is KOH.

We are given:

$n_1=2\\M_1=1.50 M\\V_1=24.7 mL\\n_2=1\\M_2=?\\V_2=90.0 mL$

Putting values in above equation, we get:

$2\times \1.50 M\times 24.7 mL=1\times M_2\times 90.0 mL$

$M_2=\frac{2\times 1.50M\times 24.7 mL}{1\times 90.0 mL}=0.823 M$

0.823 M was the molarity of the KOH solution.

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2 years ago

How do scientists use radioactive decay to date fossils

grin007 [14]

The clearer answer is they measure the remaining carbon, and the less that there is the older the fossil is.

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2 years ago