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Inessa05 [86]
2 years ago
7

What is a cell membrane​

Chemistry
2 answers:
Ray Of Light [21]2 years ago
8 0

The outer boundary of cell enclosing nucleus and cytoplasm is called cell membrane or plasma membrane.

<u>More to know</u> -

  • It is present in both plant and animal.
  • This membrane is living, thin, and delicate.
  • The cell membrane is a semi-permeable membrane, that allows the transmission of a very few molecules across it.

andrew11 [14]2 years ago
4 0

Explanation:

it's an old pic sorry

Cell membrane functions as a semi permeable barrier allowing a very few molecules across it while fencing the majority of chemicals inside cell

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A HOMOGENEOUS LIQUID THAT CANNOT BE SEPARATED INTO ITS COMPONENTS BY DISTILLATION BUT CAN BE DECOMPOSED BY ELECTROLYSIS IS CLASS
nata0808 [166]

Answer:

ELEMENTS

Explanation:

CUZ AN A

ELEMENT IS A GROUP OF ATOMS THAT CANNOT BE BROKEN DOWN BY ANY CHEMICAL OR PHYSICAL MEAN

7 0
2 years ago
Name three physical properties that differentiate oxides from hydroxide group of minerals.
erik [133]

Answer:

2k20

Explanation:

3 0
2 years ago
A mixture of gases is analyzed and found to have the following composition in mol %: CO2 12.0 CO 6.0 CH4 27.3 H2 9.9 N2 44.8 a)
vichka [17]

Answer:

a) CO₂: <em>21,9%; </em>CO: <em>7,0%; </em>CH₄: <em>18,2%; </em>H₂: <em>0,8%; </em>N₂: <em>52,1%</em>

b) 24,09 g/mol

Explanation:

a) It is posible to obtain the composition of the gas mixture in weight% using molecular mass of each compound, thus:

12% CO₂×\frac{44,01g}{1mol} = <em>528,1 g</em>

6% CO×\frac{28,01g}{1mol} = <em>168,1 g</em>

27,3% CH₄×\frac{16,05g}{1mol} = <em>438,2 g</em>

9,9% H₂×\frac{2,02g}{1mol} = <em>20,0 g</em>

44,8% N₂×\frac{28g}{1mol} = <em>1254,4 g</em>

The total mass of the gas mixture is:

528,1g + 168,1g + 438,2g + 20,0g + 1254,4g = <em>2408,8 g</em>

Thus composition of the gas mixture in weight% is:

CO₂: \frac{528,1g}{2408,8g}×100 = <em>21,9%</em>

CO: \frac{168,1g}{2408,8g}×100 = <em>7,0%</em>

CH₄: \frac{438,2g}{2408,8g}×100 = <em>18,2%</em>

H₂: \frac{20,0g}{2408,8g}×100 = <em>0,8%</em>

N₂: \frac{1254,4g}{2408,8g}×100 = <em>52,1%</em>

b) The average molecular weight of the gas mixture is determined with mole % composition, thus:

0,12×44,01g/mol + 0,06×28,01g/mol + 0,273×16,05g/mol + 0,099×2,02g/mol + 0,448×28g/mol = <em>24,09 g/mol</em>

I hope it helps!

6 0
3 years ago
How many grams of Ar are there in 2.25 moles of Ar?
Arada [10]
There will be 89.865 grams of Ar. If you put it in sig figs, it will be rounded to 89.9g At.

5 0
3 years ago
Read 2 more answers
In the three-dimensional structure of methane, ch4, the hydrogen atoms attached to a carbon atom are aligned ________. in the th
Nikitich [7]
Answer:
            In the three-dimensional structure of methane, CH₄, the hydrogen atoms attached to a carbon atom are aligned <span><u>at the corners of a Tetrahedron</u>.

Explanation:
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4 0
2 years ago
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