Question

The loss of mass in nuclear fusion is 0.02 g per mole of fuel. The molecular weight of the fuel is 5 g/mole. The amount of energy produced by consuming 1 kg of fuel in nuclear fusion is __________ kWh.

Answer 1

Answer:

The amount of energy produced by consuming 1 kg of fuel in nuclear fusion is $1.0008\times 10^8 kWh$ kWh.

Explanation:

Mass of fuel = 1 kg = 1000 g

Moles of fuel = $\frac{1000 g}{5 g/mol}=200 mole$

The loss of mass in nuclear fusion is 0.02 g per mole of fuel

Loss of mass in nuclear fusion by consuming 200 mole : m

$m=0.02 g/mol\times 200 mol = 4 g=4\times 0.001 kg$

1 g = 0.001 kg

Energy produced during this process can be determined by mass energy equation :

$E=mc^2$

$E=4\times 0.001 kg\times (3\times 10^8 m/s)^2=3.6\times 10^{14} J$

$1 J = 2.78\times 10^{-7} kWh$

$E=3.6\times 10^{14}\times 2.78\times 10^{-7} kWh=1.0008\times 10^8 kWh$

The amount of energy produced by consuming 1 kg of fuel in nuclear fusion is $1.0008\times 10^8 kWh$ kWh.