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RSB [31]
3 years ago
13

Choose one or more:

Chemistry
1 answer:
wlad13 [49]3 years ago
6 0

Answer:Electrons exhibit interference or diffraction due to scattering objects or apertures around the same size as their de Broglie wavelength. Electrons exhibit a discrete charge. Electrons exhibit a discrete mass. Electrons may tunnel through barriers of nanometer or below thickness

Explanation:

Electrons behave both as matter an waves in accordance with De Broglie principle of wave particle duality hence they possess an associated wavelength and as such undergo diffraction and interference.

Electrons have a known magnitude of mass and charge.

Many studies have also shown that electrons can tunnel through barriers of 1nm thickness or less.

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The vapor pressure of pure water at 25 °c is 23.8 torr. What is the vapor pressure (torr) of water above a solution prepared by
maxonik [38]

The vapour pressure of the solution is 23.4 torr.

Use <em>Raoult’s Law</em> to calculate the vapour pressure:  

<em>p</em>₁ = χ₁<em>p</em>₁°  

where  

χ₁ = the mole fraction of the solvent  

<em>p</em>₁ and <em>p</em>₁° are the vapour pressures of the solution and of the pure solvent  

The formula for vapour pressure lowering Δ<em>p</em> is  

Δ<em>p</em> = <em>p</em>₁° - <em>p</em>₁  

Δ<em>p</em> = <em>p</em>₁° - χ₁<em>p</em>₁° = p₁°(1 – χ₁) = χ₂<em>p</em>₁°  

where χ₂ is the mole fraction of the solute.  

<em>Step 1</em>. Calculate the <em>mole fraction of glucose </em>

<em>n</em>₂ = 18.0 g glu × (1 moL glu/180.0 g glu) = 0.1000 mol glu  

<em>n</em>₁ = 95.0 g H_2O × (1 mol H_2O/18.02 g H_2O) = 5.272 mol H_2O  

χ₂ = <em>n</em>₂/(<em>n</em>₁ + n₂) = 0.1000/(0.1000 + 5.272) = 0.1000/5.372 = 0.018 62  

<em>Step 2</em>. Calculate the <em>vapour pressure lowering</em>  

Δ<em>p</em> = χ₂<em>p</em>₁° = 0.018 62 × 23.8 torr = 0.4430 torr  

<em>Step 3</em>. Calculate the <em>vapour pressure</em>  

<em>p₁</em> = <em>p</em>₁° - Δ<em>p</em> = 23.8 torr – 0.4430 torr = 23.4 torr

3 0
3 years ago
If the dehydration reaction of an alcohol is successful. What changes would be seen in the ir spectrum for the product compared
Bess [88]

If the dehydration reaction of an alcohol is successful. The changes would be seen in the IR spectrum for the product compared to the starting material are as,

  • The O-H and  C-O  band is disappear from stating material
  • The addition of a C-C double bond band in the product.

In dehydration reaction of alcohol (  O-H and  C-O bond ) contain , the water molecule ( H_{2}O ) is release from the reactant and C-C double bond is form which is known as alkene in the product .

The reactant and product have different structure. To determine the structure of the compound IR spectroscopy is used. In IR spectrum the peak corresponds to 3400-3600 cm is missing in the product of  dehydration reaction of an alcohol. It means  O-H band is disappear from stating material.

learn about IR SPECTRUM

brainly.com/question/15452269

#SPJ4

4 0
2 years ago
Please help me !!! thank yoy
Helga [31]

Answer:

Motor Neurons.

Explanation:

Each motor neuron ending dits very close to a muscle fibre.

Hope that helps

Sorry if wrong

Have a good day

7 0
3 years ago
"Why is Co2, so bad for our bodies and why do we need to remove it?”
zavuch27 [327]
Because it is an asphyxiant.
4 0
3 years ago
Given the reaction: S + O2 ---&gt; SO2
saul85 [17]

Answer: 67.1 moles of SO2

Explanation:

Since the equation is already balanced, you would just need to cancel out the O2 and multiple the 67.1 mol by the 1 mol of SO2 to get your answer.

3 0
4 years ago
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