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wel
2 years ago
12

a blood sample analysis showed a total of 0.00467g lead. what is the result if it is expressed in micrograms?​

Chemistry
1 answer:
artcher [175]2 years ago
7 0

Answer:

4670 micrograms

Explanation:

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Which colour would you expect ekasilicon to be
LiRa [457]

Answer:

it would ether be gray to black or silver to gray and black

Explanation:

because of my calculation ekasillicon would be that color because of the eyes and because of your color seeing .

7 0
2 years ago
How much water (H2O ) would form if 4.04 g of hydrogen (H2) reacted with 31.98 g of oxygen (O2 )?
Norma-Jean [14]

Answer:

Mass = 36 g

Explanation:

Given data:

Mass of water formed = ?

Mass of hydrogen = 4.04 g

Mass of oxygen = 31.98 g

Solution:

Chemical equation:

2H₂ + O₂   →   2H₂O

Number of moles of hydrogen:

Number of moles = mass/molar mass

Number of moles = 4.04 g/ 2 g/mol

Number of moles = 2.02 mol

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles = 31.98 g/ 32 g/mol

Number of moles = 1.0 mol

Now we will compare the moles of water with hydrogen and oxygen.

                O₂         :         H₂O

                 1           :           2

                H₂         :         H₂O

                 2          :          2

               2.02       :      2.02

Number of moles of water formed by oxygen are less thus oxygen will limiting reactant.

Mass of water:

Mass = number of moles × molar mass

Mass = 2 mol × 18 g/mol

Mass = 36 g

8 0
2 years ago
Similar rock formations have been discovered in the United States and Portugal. These rock formations were formed at the same ti
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theAnswer:A

Explanation:

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2 years ago
How many chiral centres are there in warfarin molecule?
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I'm actually not sure... but maybe this will help!
http://www.dummies.com/education/science/chemistry/how-to-identify-chiral-centers-in-a-molecule/


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3 years ago
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Be sure to answer all parts. treatment of (hoch2ch2ch2ch2)2co with acid forms a product of molecular formula c9h16o2 and a molec
liubo4ka [24]
The reaction described above is the formation of an acetal. The initial starting material has a central carbonyl and two terminal alcohol functional groups. In the presence of acid, the carbonyl will become protonated, making the carbon of the carbonyl susceptible to nucleophilic attack from one of the alcohols. The alcohol substitutes onto the carbon of the carbonyl to provide us with the intermediate shown.

The intermediate will continue to react in the presence of acid and the -OH that was once the carbonyl will become protonated, turning it into a good leaving group. The protonated alcohol leaves and is substituted by the other terminal alcohol to give the final acetal product. The end result of the overall reaction is the loss of water from the original molecule to give the spiroacetal shown in the image provided.

5 0
3 years ago
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