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marshall27 [118]
3 years ago
10

Which best describes a concave lens?

Physics
1 answer:
-Dominant- [34]3 years ago
4 0

Answer:

Explanation:

Concave lens also called as diverging lens i.e. it diverges ray of light coming towards it.

Concave lens is thicker at the edges and thinner at the center.

Concave lens formed the virtual image of the object i.e. it cannot be trace on screen. This lens is used to treat the nearsightedness or myopia in which a person is unable to see the far object clearly.

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9. What is the acceleration of a boat if it starts from rest and then reaches a velocity of 24 m/s in 6.0 s?
Tom [10]

Answer:

b. 4 ms-2

Explanation:

acceleration = velocity / time

4 0
2 years ago
A kangaroo jumps straight up with an initial vertical velocity of 2.4m/s. We want to find the maximum height of the jump. We can
marishachu [46]

Answer:

v  

2

=v  

0

2

​  

+2aΔxv, squared, equals, v, start subscript, 0, end subscript, squared, plus, 2, a, delta, x

Explanation:

8 0
3 years ago
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An egg is thrown nearly vertically upward from a point near the cornice of a tall building. It just misses the cornice on the wa
Lyrx [107]

Answer:

A) 17.7 m/s

B) 15.98 m

C) Zero

E) 9.8 m/s²

Explanation:

given information

distance, h = - 34 m

time, t = 5 s

A) What is the initial speed of the egg?

h - h₀ = v₀t - \frac{1}{2} gt², h₀ = 0

- 34 = v₀ 5 - \frac{1}{2} 9.8 5²

- 34 = 5 v₀ - 122.5

v₀ = 122.5 - 34/5

    = 17.7 m/s

B) How high does it rise above its starting point?

v² = v₀² - 2gh

v = 0 (highest point)

2gh = v₀²

h = v₀²/2g

  = 17.7²/2 (9.8)

  = 15.98 m

C) What is the magnitude of its velocity at the highest point?

v = 0 (at highest point)

E) What are the magnitude and direction of its acceleration at the highest point?

g= 9.8 m/s², since the egg is moved vertically, the acceleration is the same as the gravitational acceleration.

7 0
4 years ago
How much heat must be removed
Cerrena [4.2K]

Answer:95400

Explanation:

5 0
3 years ago
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An air-filled parallel-plate capacitor has plates of area 2.30 cm2 2 separated by 1.50 mm. The capacitor is connected to a 12.0-
Gnoma [55]

Answer:

1.357\times 10^{-12}

Explanation:

Relevant Data provided

Area which indicates A = 2.3 cm^2 = 2.3 x 10^-4 m^2

Distance which indicates d = 1.50 x 10^-3 m

Voltage which indicates V = 12 V

According to the requirement, the computation of value of its capacitance is shown below:-

Capacitance, C =  \frac{\epsilon oA}{D}

= \frac{= 8.854\times 10^{-12}\times 2.3\times 10^{-4}}{(1.5 \times 10^{-3})}

= 1.357\times 10^{-12}

Therefore for computing the capacitance we simply applied the above formula.

4 0
4 years ago
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