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klemol [59]
2 years ago
10

It takes a minimum distance of 76.50 m to stop a car moving at 15.0 m/s by applying the brakes (without locking the wheels). Ass

ume that the same frictional forces apply and find the minimum stopping distance when the car is moving at 32.0 m/s.
Physics
1 answer:
Vinvika [58]2 years ago
5 0

The minimum stopping distance when the car is moving at 32.0 m/s is 348.3 m.

<h3>Acceleration of the car </h3>

The acceleration of the car before stopping at the given distance is calculated as follows;

v² = u² + 2as

when the car stops, v = 0

0 = u² + 2as

0 = 15² + 2(76.5)a

0 = 225 + 153a

-a = 225/153

a = - 1.47 m/s²

<h3>Distance traveled when the speed is 32 m/s</h3>

If the same force is applied, then acceleration is constant.

v² = u² + 2as

0 = 32² + 2(-1.47)s

2.94s = 1024

s = 348.3 m

Learn more about distance here: brainly.com/question/4931057

#SPJ1

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An investigation has been completed similar to the one on latent heat of fusion, where steam is bubbled through a container of w
allochka39001 [22]

Answer:

Q_a=330 cal

Q_w=6000cal

Explanation:

From the question we are told that

Mass of the aluminum container 50 g

Mass of the container and water 250 g

Mass of the water 200 g

Initial temperature of the container and water 20°C

Temperature of the steam 100°C

Final temperature of the container, water, and condensed steam 50°C

Mass of the container, water, and condensed steam 261 g

Mass of the steam 11 g Specific heat of aluminum 0.22 cal/g°C

a) Heat energy on container

Generally the formula for mathematically solving heat gain

      Q_c=M_c *C_c*( \triangle T)

Therefore imputing variables we have

      Q_a=50g *0.22*50-20  

      Q_a=330 cal

b) Heat energy on water

Generally the formula for mathematically solving heat gain

       Q_w=M_w *C_w*( \triangle T)

Therefore imputing variables we have

       Q_w=200 *1* 50-204

       Q_w=6000cal

7 0
3 years ago
What mass will accelerate at 3 m/s² when a net force of 150 N acts on it?
vodomira [7]

Answer:

\huge\boxed{\sf m = 50\ kg}

Explanation:

<h3><u>Given data:</u></h3>

Acceleration = a = 3 m/s²

Force = F = 150 N

<h3><u>Required:</u></h3>

Mass = m = ?

<h3><u>Formula:</u></h3>

F = ma

<h3><u>Solution:</u></h3>

Put the givens in the formula

150 = m (3)

Divide 3 to both sides

150/3 = m

50 kg = m

m = 50 kg

\rule[225]{225}{2}

7 0
2 years ago
FOR 50 POINTS! -- Your car is parked at the high school. After school you take off and travel for 27 km towards Iowa City. At th
Dovator [93]

Answer:

36km

Explanation:

Im pretty sure displacment is the start and finish in a straight line

6 0
3 years ago
Read 2 more answers
how much work does tension do on the laptop as it moves 2.0 mm ? express your answer with the appropriate units.
8090 [49]

The work done by tension force of 14N applied on the laptop by a rope as it moves 2.0 mm up the slope is 0.028 J

W = F d cos θ

W = Work done

F = Force

d = Displacement

θ = Angle between force and displacement vector

F = 14 N

d = 2 mm = 0.002 m

θ = 0

W = 14 * 0.002 * 1

W = 0.028 J

Work done is the change in energy of an object. So if an object moves a certain distance, work is done on the object. If the force and displacement are perpendicular to each other there is no work done on the object.

Therefore, the work done by tension on the laptop is 0.028 J

To know more about work done

brainly.com/question/12834956

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8 0
1 year ago
PLZ HELP photosynthesis transforms (blank)into chemical (blank)suger . cellular respration releasses the (blank) from food by (b
Alex17521 [72]

Answer is:

Photosynthesis transforms light energy into chemical energy. Cellular respration releasses the carbon dioxide from food into the air.

hope this helps :)

5 0
3 years ago
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