An experimental design is used to assign variables for testing. In contrast to a control design where nothing is changed, the experimental design allows you to test various new inputs to see how they would vary from the original results.
Answer: maximum height= 40.8m
Explanation: shown in the attachment.
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Intense temperature and pressure of regional metamorphism
Explanation:
The process that cause the formation of the Vishnu Schist is the intense temperature and pressure as a result of regional metamorphism.
- Regional metamorphism is an extensive metamorphism of an area as a result of temperature and pressure changes.
- The schist is a foliated metamorphic rock usually found in areas of moderate to high grade temperature and pressure.
- The Vishnu schist must have been metamorphosed before the new sediments were deposited on top.
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When the initial speed given is 7.5m/s at an angle of 27° , ball will go
4.637 meters.
Assume no air opposition to the ball ;
Vertical component of ball is sin 27° = 0.453
0.453* 7.5 = 3.404 meters /sec
Time taken to reach ground is :
3.404 = -3.404+9.8*t
t= 6.808/9.8= 0.694 sec
Horizontal component is 7.5*cos27°= 6.682m/s
Distance = speed * time
=6.682 * 0.694
=4.637 meters
Horizontal distance it can cover in 0.694 sec is 4.637 meters
So range of ball is 4.637 meters.
Form of motion experienced by an object or particle that is projected near surface of the earth and moves along a curve is called Projectile motion. Three types of projectile motion are Horizontal projectile motion. Oblique projectile motion and Projectile motion on an inclined plane.
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Answer:
The width of the central bright fringe on the screen is observed to be unchanged is 
Explanation:
To solve the problem it is necessary to apply the concepts related to interference from two sources. Destructive interference produces the dark fringes. Dark fringes in the diffraction pattern of a single slit are found at angles θ for which
Where,
w = width
wavelength
m is an integer, m = 1, 2, 3...
We here know that as 
as w are constant, then
We need to find 
, then
Replacing with our values:
Therefore the width of the central bright fringe on the screen is observed to be unchanged is
