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levacccp [35]
3 years ago
13

Does anyone know the answers to these?

Chemistry
1 answer:
Wewaii [24]3 years ago
5 0
Starlight is the answer for 7 and 3 is yellow
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What is limiting about a liquid Mercury thermometer?
ella [17]
There are non-mercury thermometers with temperature and accuracy rangers equal to most mercury thermometers.
8 0
3 years ago
____Cl2+____H2=____HCl
Genrish500 [490]

Answer:

<u>   </u>H2 + <u>2</u><u> </u> Cl2 = <u>2</u><u> </u> HCl2

6 0
3 years ago
NaCl has a mc020-1.jpgHfus = 30.2 kJ/mol. What is the mass of a sample of NaCl that needs 732.6 kJ of heat to melt completely?
lilavasa [31]

Answer: The mass of the sample will be 1417.7 grams.

Explanation:

We are given:

\Delta H_{fusion}=30.2kJ/mol

This means that 1 mole of NaCl has an enthalpy of fusion of 30.2 kJ

1 mole of NaCl has a mass of 58.44 grams.

So, 30.2 kJ of heat is require for a mass 58.44 grams of NaCl

So, 732.6 kJ of heat will be required for = \frac{58.44g}{30.2kJ}\times 732.6 kJ = 1417.65 grams of NaCl.

Hence, the mass of NaCl sample will be 1417.7 grams.

5 0
3 years ago
Read 2 more answers
A 10.0 cm3 sample of copper has a mass of 89.6 g. What is the density of copper
natali 33 [55]

Answer:

<h2>Density = 8.96 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

Density =  \frac{mass}{volume}

From the question

mass of copper = 89.6 g

volume = 10 cm³

Substitute the values into the above formula and solve

That's

Density =  \frac{89.6}{10}

We have the final answer as

<h3>Density = 8.96 g/cm³</h3>

Hope this helps you

7 0
3 years ago
What mass of boron sulfide must be processed with 2.1 x 10 4g of carbon to yield 3.11 x 10 4 g of boron and 1.47 x 10 5 g of car
Basile [38]

The reaction between boron sulfide and carbon is given as:

2B2S3 + 3C → 4B + 3CS2

As per the law of conservation of mass, for any chemical reaction the total mass of reactants must be equal to the total mass of the products.

Given data:

Mass of C = 2.1 * 10^ 4 g

Mass of B = 3.11*10^4 g

Mass of CS2 = 1.47*10^5

Mass of B2S3 = ?

Now based on the law of conservation of mass:

Mass of B2S3 + mass C = mass of B + mass of CS2

Mass of B2S3 + 2.1 * 10^ 4 = 3.11*10^4 + 1.47*10^5

Mass of B2S3 = 15.7 * 10^4 g


4 0
3 years ago
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